14
n has 5 valence electrons and H has 1
we have 2 N and 4 H
so 2*5 + 4*1
10+4 = 14
18
14
Calcium has a total of two valence electrons.
5
The beryllium atom has 4 electrons and the valence is 2.
Valence electrons are on the external shell.
using the crossover rule i am sure it is 4
N2+ and N2- I just did it on mastering chem and it worked I'm pretty sure its because when you count the valence electrons in N2+ and N2- you get 9 and 11 respectively because these are odd there has to be an unpaired electron in each
A silicon atom has 4 valence electrons and each hydrogen atom has one valence electron, for a total of 8.
Calcium has a total of two valence electrons.
No such thing as pi3, but if you mean PI3, then there are 5 valence electron in P, and each I has 7 valence electrons for a total of 5 + 7 + 7 + 7 = 26 valence electrons.
14 total electrons. 5 valence electrons.
It is: 0.5*(n2-3n) = diagonals.
The beryllium atom has 4 electrons and the valence is 2.
5
6 in a triple bond as in C2H2, N2
Each H has 1. Each O has 6 and the S has 6. That's a total of 32 valence electrons.
6 total valence electrons. go apex!
Valence electrons are on the external shell.