i=v/r can be used to it
In a series circuit, the current is the same throughout all components. Therefore, both ammeter 1 and ammeter 2 will read the same current, as they are measuring the same flow of electrons in the circuit. The readings on both ammeters will be equal, so neither will have a bigger reading. The voltage drop across the lamps may differ, but that does not affect the ammeter readings.
If one bulb in a series circuit blows out, the circuit becomes open, and the current stops flowing. As a result, the reading on the ammeter will drop to zero since there is no current passing through the circuit. In a parallel circuit, if one bulb blows out, the current may decrease slightly due to the change in total resistance, but the ammeter will still show a reading corresponding to the remaining bulbs in operation.
decrease to half of its original value
The Thevenin equivalent circuit of this battery is 1.5V and 0.6 ohms in series. A more exact answer cannot be given without knowing the actual resistance of the 2 meters (I assumed infinite for the voltmeter and zero for the ammeter, as would be for ideal meters).However I would NEVER attempt this test as you describe it, many types of batteries will explode like bombs when shorted (as they would be when an ammeter was placed across them)! The correct way to do this test safely is with just a voltmeter and an adjustable high wattage resistor.
If you're connecting it properly, then I would have to guess that the multimeter is defective.
If the resistor is removed from the circuit, the total resistance in the circuit decreases. This causes the total current in the circuit to increase, which would result in an increase in the ammeter reading.
The ammeter is reading zero because there is no current flowing. This is because one of the resistors is faulty; the faulty resistor has an "open circuit" (open circuit means there is a broken connection). We know that: Ohms law is: V = I x R (voltage = current x resistance) Therefore because there is zero current in each resistor there will be zero voltage across each resistor. However we also know that: Kirchhoff's voltage law is: V1 +V2 +V3 + … = Vs (the sum of the voltage drops accross each component in a circuit MUST equal the supply (or battery) voltage). But if all the resistors are zero volts, then what component equals the supply (or battery) voltage? The battery voltage is developed across the open circuit… therefore the resistor which is faulty will have a voltage across it equal to the battery voltage. That easy to measure with a volt meter! hope this helps
In a series circuit, the current is the same throughout all components. Therefore, both ammeter 1 and ammeter 2 will read the same current, as they are measuring the same flow of electrons in the circuit. The readings on both ammeters will be equal, so neither will have a bigger reading. The voltage drop across the lamps may differ, but that does not affect the ammeter readings.
it explodes and burns everyone in the room.
An ammeter reads the current that is flowing through a branch of a circuit. If there is a break within that same branch of the circuit, current will not be able to flow through that branch of the circuit as it forms an incomplete loop, so the ammeter will read 0 A of current. If there is a break in a circuit in a branch that is not connected to the ammeter however, the ammeter will give a higher reading of the current. This is assuming that the break in the other branch does not short out the branch with the ammeter attached, and that the circuit can still form a complete loop without that branch.
An open switch in a circuit will stop all current flow so the ammeter should read zero amps.
the bulb will glow and ammeter will show the reading
The voltage remains the same across the circuit as it is a parallel connection. So, the current across the upper half of the circuit where the ammeter is connected is calculated as I = V/R = 12.04 (total voltage)/12 (Resistance R1) = 1 A. Hence, the ammeter will read 1 A.
it shows some reading even though battery is low because of there will some flux remains in the magnets
If one bulb in a series circuit blows out, the circuit becomes open, and the current stops flowing. As a result, the reading on the ammeter will drop to zero since there is no current passing through the circuit. In a parallel circuit, if one bulb blows out, the current may decrease slightly due to the change in total resistance, but the ammeter will still show a reading corresponding to the remaining bulbs in operation.
An ammeter is the instrument used to measure current in an electric circuit. It is connected in series in the circuit and provides a reading of the amount of electric current flowing through it.
decrease to half of its original value