decrease to half of its original value
You'll get a reading on the ammeter showing 15 mA
Assuming the new lamp is in series, the ammeter reading falls because the total resistance has increased. By how much depends on how the lamp resistance depends on voltage. If the lamp is added in parallel to the first, then the ammeter reading doubles.
5 A
If one bulb in a series circuit blows out, the circuit becomes open, and the current stops flowing. As a result, the reading on the ammeter will drop to zero since there is no current passing through the circuit. In a parallel circuit, if one bulb blows out, the current may decrease slightly due to the change in total resistance, but the ammeter will still show a reading corresponding to the remaining bulbs in operation.
In a circuit with three cells, the ammeter reading will depend on how the cells are connected. If they are connected in series, the total voltage increases, which can lead to a higher current, assuming resistance remains constant. If they are connected in parallel, the voltage remains the same as a single cell, but the total current could increase due to the combined capacity of the cells. Therefore, the ammeter's reading will vary based on the configuration of the cells.
You would be drawing more current. It would be the same as adding more load to the circuit in a vehicle, say more lights. The lights would just be seen as more load (a resistive load in the case of incandescent lights). Add more lights (resistors) and more current is needed. The ammeter would indicate a higher current draw.
Connect ammeter in series and voltmeter in parallel to the circuit
You'll get a reading on the ammeter showing 15 mA
Assuming the new lamp is in series, the ammeter reading falls because the total resistance has increased. By how much depends on how the lamp resistance depends on voltage. If the lamp is added in parallel to the first, then the ammeter reading doubles.
If the amp meter is in series ahead of the first parallel branch of lamps the meter will read an increase in current.
The voltage remains the same across the circuit as it is a parallel connection. So, the current across the upper half of the circuit where the ammeter is connected is calculated as I = V/R = 12.04 (total voltage)/12 (Resistance R1) = 1 A. Hence, the ammeter will read 1 A.
An ideal ammeter is a device that measures electric current and has zero resistance, producing no voltage drop when connected in a circuit. This ensures that the current being measured is not affected by the presence of the ammeter itself, providing an accurate reading of the current flowing through the circuit.
5 A
If one bulb in a series circuit blows out, the circuit becomes open, and the current stops flowing. As a result, the reading on the ammeter will drop to zero since there is no current passing through the circuit. In a parallel circuit, if one bulb blows out, the current may decrease slightly due to the change in total resistance, but the ammeter will still show a reading corresponding to the remaining bulbs in operation.
The current decreases due to I=V/R. The ammeter reading will decrease as R is increased.
All the current would go through the ammeter. The whole purpose for making a measurement with an ammeter is to determine current draw through a component or circuit. If the ammeter takes all the current away from the device under test, the reading would be meaningless. Also, since the ammeter would present pretty much a dead short to the power supply, blown fuses or toasted components usually result.
In a circuit with three cells, the ammeter reading will depend on how the cells are connected. If they are connected in series, the total voltage increases, which can lead to a higher current, assuming resistance remains constant. If they are connected in parallel, the voltage remains the same as a single cell, but the total current could increase due to the combined capacity of the cells. Therefore, the ammeter's reading will vary based on the configuration of the cells.