It depends on the angle, the speed of the throw, and the mass of the object.
Surprisingly, it doesn't depend on the acceleration of gravity.
' A ' is the angle of the throw above horizontal
' V ' is the speed of the throw
' M ' is the mass of the object
The work done by gravity is:
1/2 M [ V sin(A) ]2
There are two forces on the bomb when it is dropped; horizontal, and vertical. The vertical force is gravity, and the horizontal force is the velocity of the plane when the bomb is dropped. In order to determine how far away the bomb will drop from the initial point of release, it is necessary to know the height that the plane is at, and the velocity of the plane, which is also the initial horizontal velocity of the bomb (it is constant, neglecting air resistence.)
A projectile that is thrown with an initial velocity,that has a horizontal component of 4 m/s, its horizontal speed after 3s will still be 4m/s.
The body will move: * Because of its initial motion (the question states that it is thrown) * Because of gravity
In projectile motion, since , there's no force in the horizontal direction which can change the horizontal motion therefore the horizotal velocity remains conserved Vx=Vox= Vocos theta by using above formula , constant horizontal initial or final velocity can be found. since Initial = final horizontal velocity.
Final position - Initial position
There are two forces on the bomb when it is dropped; horizontal, and vertical. The vertical force is gravity, and the horizontal force is the velocity of the plane when the bomb is dropped. In order to determine how far away the bomb will drop from the initial point of release, it is necessary to know the height that the plane is at, and the velocity of the plane, which is also the initial horizontal velocity of the bomb (it is constant, neglecting air resistence.)
We suspect that you're also given a line on the graph. If so, then the initial speed is the slope of the line at the initial position. To get the real slope of the line, you need to know the scales of the axes. If the scales aren't the same, then the real slope of the line isn't what it looks like, and has to be calculated by measuring its progress along both axes just after the initial position.
The initial position is where it starts; the final position is where it ends up.
The initial position is where it starts; the final position is where it ends up.
x
The body will move: * Because of its initial motion (the question states that it is thrown) * Because of gravity
A projectile that is thrown with an initial velocity,that has a horizontal component of 4 m/s, its horizontal speed after 3s will still be 4m/s.
If the initial velocity is v, at an angle x to the horizontal, then the vertical component is v*sin(x) and the horizontal component is v*cos(x).
The body will move: * Because of its initial motion (the question states that it is thrown) * Because of gravity
when an object shifts or is displaced from its initial position with or without acceleration then we can say that the object is moving.
In projectile motion, since , there's no force in the horizontal direction which can change the horizontal motion therefore the horizotal velocity remains conserved Vx=Vox= Vocos theta by using above formula , constant horizontal initial or final velocity can be found. since Initial = final horizontal velocity.
Final position - Initial position