The body will move:
* Because of its initial motion (the question states that it is thrown)
* Because of gravity
25feet
* Opening a circular door handle. * Revving up gas on a motorcycle * Hitting a nail with a hammer
Because it is heaver than the air. Earth attracts all bodies towards its center. So when a body is thrown upwards it rises to height and fall downwards.
Ignoring air resistance, for simplicity:* The horizontal component of the velocity (if you give it an initial thrust in any direction that is not exactly down or up) will remain unchanged, until the object touches the ground. * The vertical component of the velocity will change at a rate of about -9.8 meters per second square (assuming you define positive numbers to mean upwards).
when abody is thrown upward,how many forces act on it?what is the role of the force with which the body has been thrown upward? After a body is thrown upwards, you have gravity pulling it down and friction slowing it.
This is the vertical motion model, used when solving for height that an object is dropped from, what height an object is at after so many seconds, what rate the object is falling at, and how many seconds have passed after dropping an object when it is at x height etc. etc. Most often used in Algebra 1 and 2.
The body will move: * Because of its initial motion (the question states that it is thrown) * Because of gravity
If thrown directly upwards, it slows down due to gravitational attraction and aerodynamic drag. It reaches a maximum height and then falls. Its rate of descent is accelerated by the earth's gravity but decelerated by aerodynamic drag. If thrown at an angle, it follows a trajectory in which the vertical motion is accompanied by horizontal motion which is decelerated by aerodynamic drag.If you disregard drag, then the vertical motion is symmetrical: at any height the speed going up is exactly the same as the speed on descent. Also, for a body thrown at an angle, the trajectory is a parabola.
There is no such thing as "interconversion of body" in this case. There are energy conversions; perhaps that's what you mean?
when a body is thrown at an angle in a projectile motion, the vertical component of the velocity is vcos(B) ..where v is the velocity at which the body is thrown and B represents the angle at which it is thrown.Similarly horizontal component is vsin(B). these components are useful in determining the range of the projectile ,the maximum height reached,time of ascent,time of descent etc.,
* Opening a circular door handle. * Revving up gas on a motorcycle * Hitting a nail with a hammer
Because it is heaver than the air. Earth attracts all bodies towards its center. So when a body is thrown upwards it rises to height and fall downwards.
Ignoring air resistance, for simplicity:* The horizontal component of the velocity (if you give it an initial thrust in any direction that is not exactly down or up) will remain unchanged, until the object touches the ground. * The vertical component of the velocity will change at a rate of about -9.8 meters per second square (assuming you define positive numbers to mean upwards).
the process in which body moves around its axis and covers certain angle then this motion is called angular motion.
The ratio is 1: the motion is symmetric.
Control motion of muscles, secretions of certain organs, and send information back to the brain.
Your height determines in part just how much weight your body can reasonably carry. Weigh in excess of the healthy level for your body can certain cause health problems.
Energy is possessed by virtue of position, shape or motion or all the three properties. Generally potential energy is at first stored in a body which is released as kinetic energy when the body is in motion. But suppose if a body is thrown upwards vertically its kinetic energy gets converted into potential energy.