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Work Done = Force x Displacement, so if the displacement is zero, the work done will be zero. There will be no work done.
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How much work is done when a force is applied to an object that does not move?
Work=Force x displacement. If an object doesn't move, it is not displaced, making d=0 which means that no work is done
Does an object have to move in order for work to be done?
Work = force x distance. If distance = 0, work = 0 because force x 0 = 0.
What is The work done holding a 50 kg object at a height of 2 m above the floor for 10 seconds?
The answer is 0. If you used the formula of =>mgh, you would get a value which would be wrong. The question is a trick question. There is no work done in 'holding' an object but work would be done in 'lifting' an object. Hence, 0. ~Dartz
What can be said about a situation in which work done is negative?
the formula F.S cos angle is used (the dot product) so if angle is 0,cos angle=1 hence work done is positive and maximum if angle is 90 so cos 90 is 0 hence work done is minimum if work done is negative the angle is 180 The work done by friction is always negative (opposite the force) Since work is force x displacement, a negative value for work could mean that the displacent was negative
Work is done on an object if F equals 25 N and distance traveled by the object is 0 meters true or false?
The amount of work done on the object is (force) multiplied by (distance) = (25) x (0) = zero .
Work done is scalar or vector?
Physics as taught in high school would say that work is a scalar quantity.More sophisticated forms of physics would say that work done is a Quaternion, both a scalar and a vector.Work is bothw= [0,F][0,D]=[ 0 - F.D, 0 + 0 + FxD] = [-F.D, FxD] = -F.D + FxD. -F.D = -FDcos(FD) is scalar work out, andw= FxD= FDsin(FD) a vector called Torque.
What two condititons must be for work to be done?
work = the dot product of the force (F) and displacement vectors (D) = f * d * cos (theta), where 'f' and 'd' the magnitude of F and D, respectively; 'theta' is the angle between the two vectors. If theta = 90o, cos(theta) = 0. No work is done. That is, F is orthogonal to D. If d = 0, no work is done. That is, if the object is returning to the starting point, D = 0. ========================================
Is work being done when water freezes into ice?
The definition is that work is done when a force moves through a distance. Heat has to be removed from water to make it freeze (even if it starts as water at 0 degrees and ends as ice at 0 degrees) but no actual work is done in the process. However, because the water expands when it turns into ice some of it moves slightly. Therefore a small amount of work is, in fact, done.
How much work is done when a vertical force acts on an object moving horizontally?
as work done is dot product of force and displacement so cos(90)=0;therfore work done is zero
Example of force that moves but does no work?
work = force . distance. Since Force and distance are both vectors (work is the dot product), when the net distance = 0 (back to the point of origin), work = 0. That is, if the force is such that it moves the object back to the point of origin, it has done zero work. A centripetal force is one example. The distance = 0 when the object finishes one complete revolution. No work has been done since the beginning of the revolution.
How much work is done in closed path?
in closed path intial and final distance is same i,e change in distance=0 so work done in closed path is zero
How is work done by force measured?
You can measure the amount of work done with the formula W=Fd where W is work, F is force and d is displacement. The SI unit for work is joules (J) and if you're using thatformula, force must be in newtons (N) and displacement in meters (m). Remember that if the displacement is 0, work done is 0. If a person went around a track, and ended where he started, the displacement is 0. Displacement is the distance measures from where something starts and where it ends. Not necessarily the distance covered. Also, work is a vector quantity as is force and displacement. Hope this helps!
