Solve by factoring.
2x2 - 3x + 1 = 0
y=x+9 y'=1 x+9=0 x=-9 y=-9+9 y=0
y = 3x + y => x = 0then y = x - 9 => y = 0 - 9 = -9.
X x Y = -48 and X + Y =9 So X = 9 - Y then (9 - Y) x Y = -48 then -YxY + 9 x Y = -48 or YxY - 9 Y - 48 = 0 (rewritten) Then use discriminant, Delta = (-9)x(-9) - 4 x 1 x -48 = 273 So Y = (9 - sqrt(273)) / 2 and X = 9 - Y = 9 - ((9 - sqrt(273)) / 2 OR Y = (9 + sqrt(273)) / 2 and X = 9 - Y = 9 - ((9 + sqrt(273)) / 2
If you mean: x+y = -9 then y = -x-9 whereas the slope is -1 and the y intercept is -9
x=9; y=4; x=x+y; #x=13;y=4; y=x-y; #y=13-4=9; x=x-y; #x=13-9=4;
If: x+y = 9 then y = -x+9 whereas the slope is -1 and the y intercept is 9
x^(4)*y*x^(5)*yMultiply x^(4) by y to get x^(4)y.(d)/(dx) x^(4)*y*x^(5)*y=x^(4)y*x^(5)*yMultiply x^(4)y by x^(5) to get x^(9)y.(d)/(dx) x^(4)*y*x^(5)*y=x^(9)y*yMultiply x^(9)y by y to get x^(9)y^(2).(d)/(dx) x^(4)*y*x^(5)*y=x^(9)y^(2)To find the derivative of x^(9)y^(2), multiply the base (x) by the exponent (9), then subtract 1 from the exponent.(d)/(dx) x^(4)*y*x^(5)*y=9x^(8)y^(2)The derivative of x^(4)*y*x^(5)*y is 9x^(8)y^(2).9x^(8)y^(2)
-6
X = Y = 9 The answer must be 9, since it says it in the problem. x = 9, y=9, and x = y are all true based on the given info.
Set x=0, solve for y, which is the y intercept: 0 - 3y = 9 --> y = -3. Set y=0 and solve for x = 9 for x-intercept.
x = y+3 x+2y = 9 => x = 9-2y y+3 = 9-2y 2y+y = 9-3 3y = 6 y = 2 and x = 5
y = -5x2 - x + 9