Brown eye gene = B
Blue eye gene = b
Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb.
In this case the child will have a 50:50 chance of brown eyes if the father carries the gene for blue. But if he carries both genes for brown the child will have brown eyes.
Brown eye gene = B
Blue eye gene = b
Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb.
If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes.
If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
'phenotype' refers the visible trait. so the phenotypes would be brown eyes for the man and blue eyes for the woman.
Blue must have been dominant and brown recessive so the eyes r blue
the child received genetic information from each parent.
Because the actuality of IAIA is actually A then the father would be type A and the mother being type O they would produce children of Type A blood type. For the answer I chose A) A... I just had this on my Bio exam.
likely brown hair - in order for a red haired child both parents have to have the red hair gene & of course red hair.
well it depends on if the mother has one trait for blue eyes or not. if the mother does then there is a 1/4 chance that the child will have blue eyes and a 3/4 chance that the child will have brown eyes but if the mother does not have a blue eyed gene and she carries 2 genes for brown eyes then your child is going to have brown eyes. but no matter wat color your child's eyes are he/she will carry one gene for blue eyes and will have a possibility to pass down blue eyes to his/her child
NO
If assuming that the dominance relationship is that the brown eyed gene is dominant over the blue eyed gene. Then the child's phenotype should be brown eyes.
Yes. The father's phenotype is AO+*; the mother's is OO--.
Yes. The father's phenotype is AO+*; the mother's is OO--.
yes it dependsupon the genotype and phenotype
No. For the child to have a phenotype of O, they require an oo genotype. As the mother cannot provide one O to this, this is not possible.
i m pretty sure that child will have purple eyes
Yes. The genotypes of the father could be BO or BB (Phenotype = B) The genotype of the mother is OO(Phenotype = O) Mating these genotypes will produce either OO (Phenotype O) or BO (Phenotype B) In short, children from these parents are B or O The Rhesus(D) positive was inherited from the father.
Probably brown.
brown eyes because brown is the dominant color :)
Yes
yes, but rarely.
yes it can