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Yes, a reaction will take place. The zinc metal will displace the lead in the lead(II) sulfate solution, forming zinc sulfate and lead metal. This is because zinc is higher in the reactivity series than lead.
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Lead is less reactive than silver on the reactivity series, so lead will not replace silver in a single displacement reaction. Silver will stay as it is in the reaction.
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The reaction between lead(II) nitrate and sodium iodide is a double replacement reaction. The products of this reaction are lead(II) iodide and sodium nitrate, formed through the exchange of ions.
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When copper sulfate reacts with lead, a displacement reaction occurs where lead displaces copper from copper sulfate solution. This reaction results in the formation of lead sulfate and copper metal as products. The balanced chemical equation for this reaction is: Pb(s) + CuSO4(aq) → Cu(s) + PbSO4(s).
The chemical reaction of lead (Pb) can vary depending on the reactants involved. Lead can undergo reactions such as oxidation to form lead oxide (PbO) and reduction to form elemental lead. Lead can also react with acids to form lead salts, such as lead nitrate (Pb(NO3)2).
When solutions of lead nitrate and potassium iodide are mixed, a yellow precipitate of lead iodide is formed. This reaction is a double displacement reaction where the lead from lead nitrate reacts with the iodide from potassium iodide to form the insoluble lead iodide.
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The products of the reaction between lead(II) nitrate and sodium chloride are lead(II) chloride and sodium nitrate, which are both soluble in water. This reaction forms a white precipitate of lead(II) chloride.