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If it says CMC it is a Camshaft Machine Company Cam. their Mon-fri number is (517) 787-2040

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Q: What kind of camshaft bears this cwc or cmc 1539 112N I know it is from a Chevy 350 but is it factory?
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What kind of camshaft bears this cwc or cmc 1539 112N I know it is from a Chevy 350 but is it factory.?

If it says CMC it is a Camshaft Machine Company Cam. their Mon-fri number is (517) 787-2040


How much is an atwater kent model 112 worth?

Depends on if it has the S cabinet (112S) or N (112N).


How do you solve -26-10n102n-6?

Well, you can simplify it into 112n-32 (I have no idea if I'm doing this right). I don't really know what to do after that...


How many newtons is 73 kilograms?

73 kilograms x 9.8 newtons per kilogram (gravity pulling down on the surface of the earth) = 715.4 newtons +++ You cannot convert units of mass into unit of force. The question is based on a misunderstanding, but as the first answer hints, the force applied by a 73kg mass is 715.4N only on Earth. It will be about 112N on the Moon, roughly.


Find four consecutive odd integers if the product of the two smaller integers is 112 less than the product of the two larger integers?

11,13,15,17solve this: n(n-2)=(n-4)(n-6)+112n is the highest of the four.solving, you get:n^2 -2n=n^2-10n+1368n=136n=136/8n=17so, the four are: 11, 13, 15, 17.


Next number in sequence 20 25 32?

Any number that you choose can be the next number. It is easy to find a rule based on a polynomial of order 3 such that the first three numbers are as listed in the question followed by the chosen next number. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.For example,You want the next number to be 1? Then U(n) = (-20n^3 + 123n^2 - 214n + 171)/3You want the next number to be 2? Then U(n) = (-13n^3 + 80n^2 - 139n + 112)/2You want the next number to be 11? Then U(n) = -7n^3 + 40n^2 - 70n + 56You want the next number to be 101? Then U(n) = 10n^3 - 59n^2 + 112n - 43