Hydrogen forms positive ions.
Oxygen -2 Hydrogen +1
Oxygen -2 Hydrogen +1
Oxygen goes to -2 Hydrogen to +1
In a water molecule (H₂O), hydrogen atoms have a partial positive charge due to the differences in electronegativity between hydrogen and oxygen. Oxygen, being more electronegative, attracts the shared electrons more strongly, resulting in a partial negative charge on the oxygen atom. This creates a polar covalent bond, where the hydrogen atoms exhibit a slight positive charge compared to the more negatively charged oxygen atom.
I'm assuming you mean when they're bonded to each other - oxygen is more electronegative, so it will have a partial negative charge, and hydrogen will have a partial positive charge.
Oxygen has a higher electronegativity than hydrogen, meaning it attracts electrons more strongly. In a water molecule, the oxygen atom will partially pull the shared electrons towards itself, giving it a slightly negative charge while the hydrogen atoms have a slightly positive charge.
The oxygen atom is neutral.
The oxygen atom in O2 would have a partial negative charge due to its higher electronegativity compared to hydrogen in HCl and fluorine in F2. Oxygen tends to attract electrons more strongly, resulting in a partial negative charge on the oxygen atom in the O2 molecule.
The charge of an oxygen ion is typically -2, while the charge of a hydrogen ion is typically +1. In a polyatomic ion containing oxygen and hydrogen, the overall charge would depend on the specific arrangement and number of atoms in the ion.
No, COH4 is not a neutral compound. It would be a compound with a net charge, as the total charge of the hydrogen atoms would likely be positive and the charge of the oxygen atom would be negative.
Neither. A non-metal element has no charge, which would be required for attraction.
Water would become hydrogen peroxide (H2O2) if an extra oxygen atom is added to it. Hydrogen peroxide is a chemical compound with an additional oxygen atom compared to water, which changes its properties and reactivity.