Iron (III) Chloride Hexahydrate I think
I am assuming that this FeCl3 is going to be aqueous, as it usually is. Therefore, Fe+3 forms complexes in water in the following manner: B FeCl3(aq) +6H2O → [Fe(H2O)6]3+ Now, because the Fe has a positive charge, it will pull the negative electron cloud towards itself, making the bond holding the H on the OH weaker, which leads to an easier release of protons (H+). Therefore, [Fe(H2O)6]3+ → [Fe(H2O)5]+2 + H+ As you can see, Fe is in the "net reaction" acting as an acid, as it makes the H2O's bound to it release H+ ions into the water. Therefore, FeCl3 is assigned a Ka value, which = 2.0 x 10-3. Now, we need to set up our table: FeCl3 → Fe(H2O)5]+2 + H+ Initial concentration 0.5 M 0.0 M 0.0 M Change (-) x x x Final Concentration 0.5-x x x So, we can set up our equilibrium constant expression: Ka= [H+][ [Fe(H2O)5]+2]/[[Fe(H2O)6]3+] we know Ka therefore: 2.0 x 10-3= x2/0.5-x Solve for x, must use quadratic: 0.001-2.0 x 10-3x-x2=0 Solving the quadratic gives us: x= -0.032639, 0.030639 The negative result is unphysical, because we cannot have a negative concentration, therefore, x= 0.030639, which from our graph tells us that the concentration of H+ = 0.030639M, so to find the pH: -log( 0.030639)= pH = 1.51, so therefore, the pH of 0.5 M FeCl3 is 1.51. Hope that helps, don't know if you needed to know all the details. Praise God! Eugene.
6 CO2 + 12 H2O --> C6h12O6 + 9 O2
NiCl2 x 6 H2O Nickel(II) Chloride Hexahydride
it is 6 molecules of water
Chromium oxide is the light green inorganic compound coCr203. When dissolved in acid, it produces the hydrated chromium ions [Cr(H2O)6]3+.
The chemical reaction is:6 CO2 + 6 H2O = C6H12O6 + 6 O2
I am assuming that this FeCl3 is going to be aqueous, as it usually is. Therefore, Fe+3 forms complexes in water in the following manner: B FeCl3(aq) +6H2O → [Fe(H2O)6]3+ Now, because the Fe has a positive charge, it will pull the negative electron cloud towards itself, making the bond holding the H on the OH weaker, which leads to an easier release of protons (H+). Therefore, [Fe(H2O)6]3+ → [Fe(H2O)5]+2 + H+ As you can see, Fe is in the "net reaction" acting as an acid, as it makes the H2O's bound to it release H+ ions into the water. Therefore, FeCl3 is assigned a Ka value, which = 2.0 x 10-3. Now, we need to set up our table: FeCl3 → Fe(H2O)5]+2 + H+ Initial concentration 0.5 M 0.0 M 0.0 M Change (-) x x x Final Concentration 0.5-x x x So, we can set up our equilibrium constant expression: Ka= [H+][ [Fe(H2O)5]+2]/[[Fe(H2O)6]3+] we know Ka therefore: 2.0 x 10-3= x2/0.5-x Solve for x, must use quadratic: 0.001-2.0 x 10-3x-x2=0 Solving the quadratic gives us: x= -0.032639, 0.030639 The negative result is unphysical, because we cannot have a negative concentration, therefore, x= 0.030639, which from our graph tells us that the concentration of H+ = 0.030639M, so to find the pH: -log( 0.030639)= pH = 1.51, so therefore, the pH of 0.5 M FeCl3 is 1.51. Hope that helps, don't know if you needed to know all the details. Praise God! Eugene.
6 CO2 + 12 H2O --> C6h12O6 + 9 O2
C3H6O the 3 and 6 are subscripts
These are some possible ionic equation for CuSO4 plus H2O: Cu2+ + 6 H2O --> Cu(H2O)6 Cu(H2O)62+ + H2O <--> Cu(OH)(H2O)5+ + H3O+ This makes a solution of copper sulfate weakly acidic.
NiCl2 x 6 H2O Nickel(II) Chloride Hexahydride
I assume you mean Cellular Respiration. Aerobic Respiration Chemical Equation C6H12O6 + 6 O2 + 6 H2O --> 6 CO2 + 12 H2O + Energy (as ATP) Simply put C6H12O6 + 6 O2 + 6 H2O is broken down into 6 CO2 + 12 H2O + Energy (as ATP) through Cellular Respiration
it is 6 molecules of water
Chromium oxide is the light green inorganic compound coCr203. When dissolved in acid, it produces the hydrated chromium ions [Cr(H2O)6]3+.
Using sunlight,6 CO2 + 12 H2O ===> C6H12O6 + 6 H2O + 6 O2http://en.wikipedia.org/wiki/Photosynthesis
This reaction is:S + 6 HNO3 = H2SO4 + 2 H2O + 6 NO2
2Na + 2H2O = 2NaOH + H2 2Na + 2HCl = 2NaCl + H2 Na+H2O= NaOH2