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Yes, in a Lewis diagram, the valence electrons are shown by dots around them.
The diagram shows the valence of the atom.
1. An electron dot diagram can show you that the symbols for an element surrounded by dots. Each dot stands for one valence electron.
Because they have only one electron in their valency shell. The second oxidation state would require the atom to lose an electron from its penultimate shell which is full.
i need to know this information and much more information for school. and i wish you can help me on it. what does a dot diagram show? what are two things a dot diagram must show? how can the group number help in determining the number of valence electrons? what is true for the dot diagram for every element in a group? what is helium's dot diagram? why is helium's dot diagram different? what do electron configurations show? how is the total number of electrons for an aton determined? what do all the number in the electron configuration equal to? why is knowing the period an element is in necessary to write a correct electron configuration? what does the group number tell us about the electron configuration? what are the electron configurations of Lithium (Li), Carbon (C), Magnesium (Mg), Silicon (Si), Chlorine (Cl), Potassium (K)?
Yes, in a Lewis diagram, the valence electrons are shown by dots around them.
It shows the number of valence electrons (outer shell electrons available to be lost) and whether they are paired or single.
dots in an electron shell
The diagram shows the valence of the atom.
1. An electron dot diagram can show you that the symbols for an element surrounded by dots. Each dot stands for one valence electron.
Because copper loose electron from its penultimate outer shell
cycle diagram
eight.
The electron-dot representation of a carbon atom show only four dots because the dots represent only the valence electrons (the ones placed in the outermost shell). The carbon atom has four electrons in it's outermost shell. !
What kind? like the circle kind? Venndiagram?
Because they have only one electron in their valency shell. The second oxidation state would require the atom to lose an electron from its penultimate shell which is full.
With a pencil. Or a pen; I'm that confident. The best suggestion I can give to you is to follow the given directions; they seem pretty straightforward to me.