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Who lives in a log cabin?
emagrants
How do you solve k equals log4 91.8?
k=log4 91.8 4^k=91.8 -- b/c of log rules-- log 4^k=log 91.8 -- b/c of log rules-- k*log 4=log91.8 --> divide by log 4 k=log 91.8/log 4 k= 3.260
What company logo has a red circle with a white r in it?
The company that has a red circle logo with a white R in it is Rossignol
What is the untiderivative of k to the power of x?
If in the real number universe, first k is to be >0, y=kx = exlog(k) the antiderivative of eax is eax/a so the antiderivative of Y is exlog(k) / log(k) = kx /log(k)
What is log k?
It is a number such that, if 10 were raised to that power, the answer would be k. ie 10log k = k
Where can you find the k-swiss red ariake shoes?
I purchased a pair with black and white and the came with black/red checkerboard laces on e bay
Where can you find the k Swiss red ariake shoes?
I purchased a pair with black and white and the came with black/red checkerboard laces on e bay
Pascal's triangle using q-basic?
You could just use the binomial theorem. Step through rows, n, and entries, k, and compute the Pascal's triangle value as n!/(k!*(n-k)!) You'll actually have better luck if you use the natural log of a factorial, then you can use laws of exponents to get: exp(log(n!/k!/(n-k)!)) = exp(log(n!)-log(k!)-log((n-k)!)) = exp(logfact(n)-logfact(k)-logfact(n-k)) which won't run into the integer overflow problems that a plain factorial function would have. To fill up a logfact array, something like this might work: while(i<maxn) logfact(i)=logfact(i-1)+log(i) i=i+1 Wend Be careful to initialize correctly, and watch your conversion between integers and doubles (probably have to do some rounding to your final answers).
What is the exponential function in the form y equals c times e to the power of kx that passes through the points 1 180 and 3 20?
y = c ekxpassing through (1, 180) and (3, 20).(Note: All of the 'log' in the following are natural logs.)log(y) = log(c) + k log(x)Log(180) = log(c) + k log(1) = log(c)c = 180log(20) = log(180) + k log(3)log(20) - log(180) = k log(3)k = log(20/180) / log(3) = - log(9) / log(3) = -2y = 180 e-2xIn checking my work, I find that this doesn't work at all.Oh woe! Where have I failed ?--------------------------------------------Here's what I did:y=Cekx which passes through the points (1,180) & (3,20)(1) Substitute the values of x & y to create two equations:180 = Cek & 20 = Ce3k(2) Rearrange in terms of the constant, C:C=180/ek & C=20/e3k(3) Since both sets of points satisfy the exponential function, the constant will be the same so:180/ek = 20/e3k(4) Now rearrange and solve for k:180e3k = 20ek9 = e(k-3k)ln(9) = ln(e-2k)ln(9) = -2kk = -ln(9)/2 which is approx. -1.09861(5) Now substitute k into one of the equations to solve for C:C =180/e(-1.09861)C = 539.9987 or rounded to 540So the exponential function that includeds the points (1,180) & (3,20) can be approximated as:y = 540ekx , where k = -1.09861
When was Michael K. White born?
Michael K. White was born in 1961.
Is a white and blue star hotter then a red star?
Yes. See the Wikipedia article on "Stellar classification". For example, a class "O" star (blue) has a surface temperature greater than 30,000 K, a class "A" star (white) has a surface temperature of 7,500 - 10,000 K, and a class "M" star (red) has a surface temperature of 2400-3700 K. (All temperatures use the absolute scale.)
What is specific growth rate constant?
it is used as a way of measuring how fast cells are dividing, defined as the doubling rate, and it is worked out with the following formula: k=(Log Nt - Log No)/ t x Log 2 this goes to the slightly easier form of; k= 3.32 x (Log Nt - Log No)/ t where k= growth rate constant Nt = number of bacteria at second time No = number bacteria at start t = time gone. (obvioulsy you take the logs of Nt and No in the formula)
