The answer is 49,29 g CCl4.
1. Convert 6.32 mg to grams.6.32 mg x 1g/1000 mg = 0.00632 g2. Determine the molar mass for CCl4.The molar mass is 153.82g/mol (Wikipedia)3. Convert given mass to moles using the molar mass.0.00632 g CCl4 x 1 mol CCl4/153.82 g CCl4 = 4.11 x 10^-5 mol CCl44. Convert moles to molecules.One mole of molecules is 6.022 x 10^23 molecules.4.11 x 10^-5 mol CCl4 x 6.022 x 10^23 molecules CCl4/mol CCl4 = 2.47 x 10^19 molecules CCl4
Divide the Molar Mass of C and Cl4 by 56 to get your awnswer!
6,26 g CuO are obtained.
The mass of all substances before a chemical reaction is equal to the mass of the substance after the reaction. This is under the law of conservation of mass.
340 grams
76.7g
2,74 moles of CCL4 is equivalent to 421,44 g.
1. Convert 6.32 mg to grams.6.32 mg x 1g/1000 mg = 0.00632 g2. Determine the molar mass for CCl4.The molar mass is 153.82g/mol (Wikipedia)3. Convert given mass to moles using the molar mass.0.00632 g CCl4 x 1 mol CCl4/153.82 g CCl4 = 4.11 x 10^-5 mol CCl44. Convert moles to molecules.One mole of molecules is 6.022 x 10^23 molecules.4.11 x 10^-5 mol CCl4 x 6.022 x 10^23 molecules CCl4/mol CCl4 = 2.47 x 10^19 molecules CCl4
2.55 × 10 − 22 g
CO2 gas is formed, and as it is leaving the instrument in which this reaction is done in, the mass decreases.
The mass is 58,44 g NaCl.
The molar mass of CCl4 is 153,82 g.153,82 ------------------------------------6,02214129.10ex.23 (Avogadro number)22,4 g-------------------------------------xx = 0,877.10ex.23 molecules
Divide the Molar Mass of C and Cl4 by 56 to get your awnswer!
6,26 g CuO are obtained.
exactly 100,0913 XD glad I could help
The atomic number is 2, and the atomic mass is 4 (helium)
The mass of all substances before a chemical reaction is equal to the mass of the substance after the reaction. This is under the law of conservation of mass.