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What mass of nitrogen and hydrogen needed to produce 91.3 Kg of ammonia?
Wiki User
∙ 14y ago
Ammonia-NH3
2N+3H2=2NH3
2moles of Nitrogen produced 2moles of Ammonia
(2*14)g of Nitrogen produced (2*17)g of Ammonia
28g of Nitrogen produced 34g of Ammonia
34g of Ammonia is produced by 28g of Nitrogen
0.034kg of Ammonia is produced by 0.028kg of Nitrogen
91.3kg of Ammonia will be produced by 0.028*91.3/0.034
91.3kg of Ammonia will be produced by 75.19kg of Nitrogen
FOR HYDROGEN: 3moles of H2 produces 2moles of NH3
(2*3)g H2 produces 2*17g NH3
6g hydrogen produces 34g ammonia
0.006kg hydrogen produces o.o34kg ammonia
91.3kg ammonia will be produced by 91.3*0.006/.034=16.11kg of Hydogen
Therefore, 75.19kg of Nitrogen and 16.11kg of Hydrogen will produce 91.3kg of Ammonia
Wiki User
∙ 14y ago
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What mass of nitrogen is needed to make 34 grams of ammonia?
28 grams of Nitrogen is necessary to produce 34 grams of ammonia.
How many moles of nitrogen and hydrogen are needed to get 10 moles of ammonia?
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
How many moles of hydrogen are required to produce 18.00 moles of ammonia?
N2 + 3H2 -> 2NH3 The stoichiometric equation (or balanced equation) for the formation of ammonia from this we can read off the mole ratio between hydrogen and ammonia; 3M H2 needed to produce 2M NH3 times each by 9 (so the ratio remains the same and 18M NH3 is formed) 27M H2 needed to produce 18M NH3
How many grams of nitrogen are needed to produce 660 grams of ammonia?
The equation for the formation of ammonia from nitrogen and hydrogen gases at standard temperature and pressure is N2 + 3 H2 -> 2 NH3. The gram molecular mass of ammonia is 17.03 and the gram molecular mass of divalent nitrogen is 28.0134. Therefore, designating the unknown mass of nitrogen needed as p, the proportion 660/p equals (2 X 17.03)/28.0134 is valid. This expression is algebraically equivalent to 660 = (34.06)p/28.0134, for which p = 543 grams, rounded to the justified number of significant digits, limited by the three significant digits specified by the given number 600.
In order to get 1 mole of ammonia how many moles of nitrogen is needed?
Each mole of ammonia requires one mole of nitrogen atoms. However, the nitrogen in the air occurs as diatomic molecules; therefore, only one-half mole of molecular nitrogen is required for each mole of ammonia.
What element is needed to create ammonia?
Nitrogen and Hydrogen.
What mass of nitrogen is needed to make 34 grams of ammonia?
28 grams of Nitrogen is necessary to produce 34 grams of ammonia.
How many moles of ammonia are needed to produce 3.5 mole of nitrogen?
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
How many moles of nitrogen and hydrogen are needed to get 10 moles of ammonia?
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
How many hydrogen atoms would be needed to bond with one nitrogen atom to stabilize all atoms?
Three hydrogen atoms would be needed to bond with one nitrogen atom and the name of this molecule is ammonia.
How many moles of hydrogen are required to produce 18.00 moles of ammonia?
N2 + 3H2 -> 2NH3 The stoichiometric equation (or balanced equation) for the formation of ammonia from this we can read off the mole ratio between hydrogen and ammonia; 3M H2 needed to produce 2M NH3 times each by 9 (so the ratio remains the same and 18M NH3 is formed) 27M H2 needed to produce 18M NH3
How many moles of nitrogen are needed to convert 9.0 mole hydrogen gas to ammonia gas?
To form ammonia, balanced reaction is N(2) + 3H(2) ---> 2NH(3) + H(2)O. As you can see for 1 mole of nitrogen three moles of hydrogen is required. Hence for your question, 3 moles nitrogen is required to satisfy the ratio.
How many moles of nitrogen are needed to convert 9.0 mol hydrogen gas to ammonia gas?
According balanced equation ,3 mols are needed. So 3mol shoul be mixed
How many moles of hydgrogen are needed to produce 6.0 moles of ammonia?
This is based on calculations too. It contains 18 hydrogen moles.
How many grams of nitrogen are needed to produce 660 grams of ammonia?
The equation for the formation of ammonia from nitrogen and hydrogen gases at standard temperature and pressure is N2 + 3 H2 -> 2 NH3. The gram molecular mass of ammonia is 17.03 and the gram molecular mass of divalent nitrogen is 28.0134. Therefore, designating the unknown mass of nitrogen needed as p, the proportion 660/p equals (2 X 17.03)/28.0134 is valid. This expression is algebraically equivalent to 660 = (34.06)p/28.0134, for which p = 543 grams, rounded to the justified number of significant digits, limited by the three significant digits specified by the given number 600.
How many grams of H2 are needed to produce 14.59g of NH3?
The atomic mass of hydrogen is 1.008 and that of nitrogen is 14.007. Therefore, the ratio of the mass of hydrogen to the total mass of NH3 must be 3(1.008)/[14.007 + 3(1.008)] = 0.17756. The mass of hydrogen in the stated amount of ammonia must therefore be 14.59(0.17756) = 2.591 g, to the justified number of significant digits.
In order to get 1 mole of ammonia how many moles of nitrogen is needed?
Each mole of ammonia requires one mole of nitrogen atoms. However, the nitrogen in the air occurs as diatomic molecules; therefore, only one-half mole of molecular nitrogen is required for each mole of ammonia.
