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How many moles for silver chloride are produced from 7 mol of silver nitrate?
Since both chloride anions and nitrate anions have a charge of -1, there will be the same number of moles of silver chloride produced as the moles of silver nitrate reacted. (Since both silver nitrate and silver chloride are ionic compounds, it would be preferable to call their "moles" "formula units" instead.)
In the reaction of silver nitrate with sodium chloride how many grams of silver chloride will be produced from 100 g of silver nitrate when it is mixed with an excess of sodium chloride?
When silver nitrate reacts with sodium chloride, silver chloride is formed according to the equation: AgNO3 + NaCl -> AgCl + NaNO3. The molar ratio of silver nitrate to silver chloride is 1:1. Therefore, 100 g of silver nitrate will produce 143.32 g of silver chloride.
How many moles of silver chloride can be produced from 7.0 mol of silver nitrate?
One mole of silver nitrate reacts with one mole of sodium chloride to produce one mole of silver chloride. Therefore, 7.0 mol of silver nitrate will produce 7.0 mol of silver chloride.
What mass of silver chloride can be produced from 1.85 L of a 0.141 M solution of silver nitrate?
First, calculate the moles of silver nitrate in the solution using Molarity = moles/volume. Then, use the balanced chemical equation between silver nitrate and silver chloride to determine the moles of silver chloride that can be produced. Finally, convert the moles of silver chloride to grams using the molar mass of silver chloride.
What mass of silver chloride can be produced from 1.59L of a 0.300M solution of silver nitrate?
To find the mass of silver chloride produced, first calculate the moles of silver nitrate using Molarity = moles/volume. Then, use the mole ratio from the balanced chemical equation to find the moles of silver chloride produced. Finally, multiply the moles of silver chloride by its molar mass to find the mass of silver chloride produced.
What mass of silver chloride can be produced from 1.99 L of a 0.104 M solution of silver nitrate?
To calculate the mass of silver chloride produced, we need to use the concept of stoichiometry. Firstly, write the balanced chemical equation for the reaction between silver nitrate and sodium chloride. Then, use the molarity of silver nitrate and the stoichiometry of the reaction to find the moles of silver chloride produced. Finally, convert the moles of silver chloride to grams using its molar mass.
How many grams of silver chloride are formed when 10.0 g of silver nitrate reacts with 15.0 g of barium chloride?
To find the limiting reactant, we need to determine how many grams of silver chloride can be produced from each reactant and compare the results. Calculate the amount of silver chloride that can be produced from 10.0 g of silver nitrate. Calculate the amount of silver chloride that can be produced from 15.0 g of barium chloride. The reactant that produces the lesser amount of silver chloride will be the limiting reactant.
potassium chloride + silver nitrate yields potassium nitrate + silver chloride?
no
What mass of silver chloride can be produced from 1.17 L of a 0.219 M solution of silver nitrate?
To find the mass of silver chloride produced, we need to calculate the moles of silver nitrate using the given volume and concentration. Then, we use the stoichiometry of the balanced chemical equation to determine the moles of silver chloride formed. Finally, we convert the moles of silver chloride to grams using its molar mass.
What happens when silver nitrate reacts with ammonium chloride?
When silver nitrate reacts with ammonium chloride, a white precipitate of silver chloride forms along with ammonium nitrate. This reaction is a double displacement reaction where the silver ion in the silver nitrate switches places with the ammonium ion in the ammonium chloride, resulting in the formation of the two new compounds.
What happens when silver nitrate is added to barium chloride?
When silver nitrate is added to barium chloride, a white precipitate of silver chloride forms because silver chloride is insoluble in water. This occurs due to a double displacement reaction where the silver ions from silver nitrate react with the chloride ions from barium chloride to form silver chloride. The remaining solution would contain barium nitrate as the other product of the reaction.
What happened silver nitrate added ammonium chloride?
When silver nitrate is added to ammonium chloride, a white precipitate of silver chloride is formed. This reaction is a double displacement reaction, where silver cations from silver nitrate combine with chloride anions from ammonium chloride to form the insoluble silver chloride precipitate.
