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Since both chloride anions and nitrate anions have a charge of -1, there will be the same number of moles of silver chloride produced as the moles of silver nitrate reacted. (Since both silver nitrate and silver chloride are ionic compounds, it would be preferable to call their "moles" "formula units" instead.)
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How many moles of silver chromate (Ag2CrO4) will be produced from 4 mol of silver nitrate (AgNO3)?
Since silver chromate has a 1:1 molar ratio with silver nitrate, 4 moles of silver nitrate will produce 4 moles of silver chromate.
How do you calculate the percent chloride with the volhard method?
To calculate the percent chloride using the Volhard method, you measure the excess silver nitrate used to titrate the chloride ions in the sample. You then use the volume of excess silver nitrate and the molarity of the silver nitrate solution to calculate the moles of chloride present. Finally, calculate the percent chloride by dividing the moles of chloride by the sample weight and multiplying by 100.
How many grams of silver nitrate can be produced by the reaction of 100.0 ml of 0.20 M silver nitrate and 100.0 ml of 0.15 M calcium chloride?
To find how many grams of silver nitrate can be produced, first determine the limiting reactant. Calculate the moles of silver nitrate and calcium chloride in the given volumes and concentrations. The reactant that produces fewer moles of silver nitrate will be the limiting reactant. Then use stoichiometry to find the amount of silver nitrate that can be produced from the limiting reactant.
How many moles of silver nitrate are needed to completely react with 0.327 mole of sodium cloride?
The balanced equation for the reaction is AgNO3 (aq) + NaCl (aq) -> AgCl (s) + NaNO3. The coefficient of each reactant is the implied 1 when no explicit coefficient is shown in the equation. Therefore the same number of moles of silver nitrate as of sodium chloride are required for the reaction.
Hoy many moles of potassium nitrate are produced when 2 moles of potassium phosphate react wth 2 moles of aluminum nitrate?
The balanced equation for this reaction is: 2K3PO4 + 3Al(NO3)3 -> 6KNO3 + AlPO4. This indicates that 2 moles of potassium phosphate react with 2 moles of aluminum nitrate to produce 6 moles of potassium nitrate.
What mass of silver chloride can be produced from 1.85 L of a 0.141 M solution of silver nitrate?
First, calculate the moles of silver nitrate in the solution using Molarity = moles/volume. Then, use the balanced chemical equation between silver nitrate and silver chloride to determine the moles of silver chloride that can be produced. Finally, convert the moles of silver chloride to grams using the molar mass of silver chloride.
What mass of silver chloride can be produced from 1.59L of a 0.300M solution of silver nitrate?
To find the mass of silver chloride produced, first calculate the moles of silver nitrate using Molarity = moles/volume. Then, use the mole ratio from the balanced chemical equation to find the moles of silver chloride produced. Finally, multiply the moles of silver chloride by its molar mass to find the mass of silver chloride produced.
How many moles of silver chloride are produced from 7 moles of silver nitrate?
1 mole of silver nitrate produces 1 mole of silver chloride in a 1:1 ratio according to the balanced chemical equation AgNO3 + NaCl -> AgCl + NaNO3. Therefore, 7 moles of silver nitrate will produce 7 moles of silver chloride.
What mass of silver chloride can be produced from 1.17 L of a 0.219 M solution of silver nitrate?
To find the mass of silver chloride produced, we need to calculate the moles of silver nitrate using the given volume and concentration. Then, we use the stoichiometry of the balanced chemical equation to determine the moles of silver chloride formed. Finally, we convert the moles of silver chloride to grams using its molar mass.
What mass of silver chloride can be produced from 1.99 L of a 0.104 M solution of silver nitrate?
To calculate the mass of silver chloride produced, we need to use the concept of stoichiometry. Firstly, write the balanced chemical equation for the reaction between silver nitrate and sodium chloride. Then, use the molarity of silver nitrate and the stoichiometry of the reaction to find the moles of silver chloride produced. Finally, convert the moles of silver chloride to grams using its molar mass.
How many moles of silver chloride can be produced from 7.0 mol of silver nitrate?
One mole of silver nitrate reacts with one mole of sodium chloride to produce one mole of silver chloride. Therefore, 7.0 mol of silver nitrate will produce 7.0 mol of silver chloride.
How many moles of silver are produced from 7 moles of silver nitrate?
1 mole of silver nitrate produces 1 mole of silver when it reacts to completion. Therefore, 7 moles of silver nitrate will produce 7 moles of silver.
What mass of silver chloride can be produced from 1.88 L of a 0.139 M solution of silver nitrate?
Since the four named compounds are the only reactants and products, this question can be answered from the law of conservation of mass: The amount of silver nitrate must be 14.35 + 8.5 - 5.85 or 17.0 grams.
What mass of silver chloride can be produced from 1.75L of a 0.293M solution of silver nitrate?
To determine the mass of silver chloride produced, we need to know the balanced chemical equation for the reaction between silver nitrate (AgNO3) and sodium chloride (NaCl) that produces silver chloride (AgCl) as a precipitate. Once we have the balanced equation, we can use the stoichiometry of the reaction to determine the number of moles of AgCl produced, and then convert that to mass using the molar mass of AgCl.
How many moles of silver chromate (Ag2CrO4) will be produced from 4 mol of silver nitrate (AgNO3)?
Since silver chromate has a 1:1 molar ratio with silver nitrate, 4 moles of silver nitrate will produce 4 moles of silver chromate.
How do you calculate the percent chloride with the volhard method?
To calculate the percent chloride using the Volhard method, you measure the excess silver nitrate used to titrate the chloride ions in the sample. You then use the volume of excess silver nitrate and the molarity of the silver nitrate solution to calculate the moles of chloride present. Finally, calculate the percent chloride by dividing the moles of chloride by the sample weight and multiplying by 100.
How many grams of silver nitrate can be produced by the reaction of 100.0 ml of 0.20 M silver nitrate and 100.0 ml of 0.15 M calcium chloride?
To find how many grams of silver nitrate can be produced, first determine the limiting reactant. Calculate the moles of silver nitrate and calcium chloride in the given volumes and concentrations. The reactant that produces fewer moles of silver nitrate will be the limiting reactant. Then use stoichiometry to find the amount of silver nitrate that can be produced from the limiting reactant.
