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In this reaction, the precipitate formed would be silver chromate due to the double displacement reaction between sodium chromate (Na2CrO4) and silver nitrate (AgNO3). Silver chromate is insoluble in water, so it will precipitate out of the solution as a solid, appearing as a yellow precipitate.
2Ag(aq)+ CrO4(s)---->AgCrO4(s)
The light yellow solution is likely to be sodium chromate. This solution would give a white precipitate of silver chromate when treated with acidified silver nitrate due to the formation of a sparingly soluble salt, Ag2CrO4.
The solubility product expression for silver chromate (Ag2CrO4) is Ksp = [Ag+]²[CrO4²-], where [Ag+] represents the concentration of silver ions and [CrO4²-] represents the concentration of chromate ions in the saturated solution.
the Molecular equation would be AgNO3 + Na2CrO4 =yields= Ag2CrO4 + NaNO3 On the product side the silver cromate is insoluble, therefore it will form a precipitate remember everything is aquous (aq) except the silver cromate it is solid (s) Net Ionic equation is Ag(aq) + CrO4 -2 (aq) > Ag2CrO4(s)
The chemical formula of silver chromate is Ag2CrO4.
The chemical formula for silver chromate is Ag2CrO4.
The ionic equation for the reaction between silver nitrate (AgNO3) and potassium chromate (K2CrO4) is: Ag+ + 2NO3- + 2K+ + CrO42- -> Ag2CrO4(s) + 2KNO3 This reaction forms silver chromate (Ag2CrO4) as a solid precipitate, with potassium nitrate (KNO3) remaining in solution.
In this reaction, the precipitate formed would be silver chromate due to the double displacement reaction between sodium chromate (Na2CrO4) and silver nitrate (AgNO3). Silver chromate is insoluble in water, so it will precipitate out of the solution as a solid, appearing as a yellow precipitate.
2Ag(aq)+ CrO4(s)---->AgCrO4(s)
Silver chromate has a brown red colour
The light yellow solution is likely to be sodium chromate. This solution would give a white precipitate of silver chromate when treated with acidified silver nitrate due to the formation of a sparingly soluble salt, Ag2CrO4.
That is, Ag2CrO4 Ag + and CrO4 2- come together to form Ag2CrO4 Silver chromate --------------------
The Ksp expression for silver chromate (Ag2CrO4) is: Ksp = [Ag+]^2 * [CrO4^2-]
No, Ag2CrO4 (silver chromate) is not soluble in water. It is considered insoluble in water at room temperature.
Two types: silver (Ag+) and chromate (CrO4-2) And within the formula (Ag2CrO4) there are two silver ions and one chromate ion for a total of three ions.
The solubility product expression for silver chromate (Ag2CrO4) is Ksp = [Ag+]²[CrO4²-], where [Ag+] represents the concentration of silver ions and [CrO4²-] represents the concentration of chromate ions in the saturated solution.