Ag2CrO4 should form a clay red precipitate which doesn't dissolve in acid.
Since silver chromate has a 1:1 molar ratio with silver nitrate, 4 moles of silver nitrate will produce 4 moles of silver chromate.
The chromate ion (CrO4-2) has yellow colour so all the chromate compounds including silver chromate is yellow in colour.
The precipitate formed from the reaction between silver nitrate and potassium chloride is white in color. This precipitate is silver chloride, which is insoluble in water and forms when the silver ions from silver nitrate react with chloride ions from potassium chloride.
the chemical reaction between silver nitrate and potassium chromate in generally used in a titration to look for chloride ions , and is a two step reaction: i will give you the ionic equations, which is pretty much all you need Ag+(aq) + Cl-(s) --> AgCl(s) this part of the equation caused the solution to go cloudy. when all the chloride ions are used up then the silver reacts with the chromate ions to produce the red colour you see when the end point of the precipitation is reached: 2Ag+(aq) + CrO4 2-(aq) --> Ag2 CrO4(s) which produces the red colour the amount of silver nitrate relates directly to the chloride ion concentration as it is a 1:1 ration reaction. i hope this answers your question =)
When silver nitrate reacts with ammonium chloride, a white precipitate of silver chloride forms along with ammonium nitrate. This reaction is a double displacement reaction where the silver ion in the silver nitrate switches places with the ammonium ion in the ammonium chloride, resulting in the formation of the two new compounds.
The number of moles of silver chromate formed will depend on the stoichiometry of the reaction between silver nitrate and potassium chromate. You need to know the balanced chemical equation, as well as the exact volumes and concentrations of the silver nitrate and potassium chromate solutions to calculate the number of moles of silver chromate formed.
Silver chromate is not soluble in water.
Potassium Chromate precipitates with and coumpnd that contains a cation and NO3, also known as the polyatomic ion Nitrate. Three common examples of this are Zinc Nitrate (Zn(NO3)2) Silver Nitrate (AgNO3) and Baruim Nitrate (Ba(NO3)2)
Since silver chromate has a 1:1 molar ratio with silver nitrate, 4 moles of silver nitrate will produce 4 moles of silver chromate.
The chromate ion (CrO4-2) has yellow colour so all the chromate compounds including silver chromate is yellow in colour.
The precipitate formed from the reaction between silver nitrate and potassium chloride is white in color. This precipitate is silver chloride, which is insoluble in water and forms when the silver ions from silver nitrate react with chloride ions from potassium chloride.
When silver nitrate reacts with hydrochloric acid, silver chloride and nitric acid are formed. This reaction is a double displacement reaction where the silver ions from silver nitrate combine with the chloride ions from hydrochloric acid to form silver chloride, which is insoluble and precipitates out of solution. This reaction is often used as a test for the presence of chloride ions in a solution.
The ionic equation for the reaction between silver nitrate (AgNO3) and potassium chromate (K2CrO4) is: Ag+ + 2NO3- + 2K+ + CrO42- -> Ag2CrO4(s) + 2KNO3 This reaction forms silver chromate (Ag2CrO4) as a solid precipitate, with potassium nitrate (KNO3) remaining in solution.
the chemical reaction between silver nitrate and potassium chromate in generally used in a titration to look for chloride ions , and is a two step reaction: i will give you the ionic equations, which is pretty much all you need Ag+(aq) + Cl-(s) --> AgCl(s) this part of the equation caused the solution to go cloudy. when all the chloride ions are used up then the silver reacts with the chromate ions to produce the red colour you see when the end point of the precipitation is reached: 2Ag+(aq) + CrO4 2-(aq) --> Ag2 CrO4(s) which produces the red colour the amount of silver nitrate relates directly to the chloride ion concentration as it is a 1:1 ration reaction. i hope this answers your question =)
When silver nitrate reacts with ammonium chloride, a white precipitate of silver chloride forms along with ammonium nitrate. This reaction is a double displacement reaction where the silver ion in the silver nitrate switches places with the ammonium ion in the ammonium chloride, resulting in the formation of the two new compounds.
When sodium carbonate reacts with silver nitrate, the double displacement reaction forms silver carbonate, which is insoluble in water and precipitates out of the solution. The remaining products are sodium nitrate, which remains dissolved in the solution.
When silver nitrate is added to ammonium chloride, a white precipitate of silver chloride is formed. This reaction is a double displacement reaction, where silver cations from silver nitrate combine with chloride anions from ammonium chloride to form the insoluble silver chloride precipitate.