That is,
Ag2CrO4
Ag + and CrO4 2-
come together to form Ag2CrO4
Silver chromate
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The Ksp expression for silver chromate (Ag2CrO4) is: Ksp = [Ag+]^2 * [CrO4^2-]
Two types: silver (Ag+) and chromate (CrO4-2) And within the formula (Ag2CrO4) there are two silver ions and one chromate ion for a total of three ions.
No. It is an ionic compound composed of the lead IV cation (Pb4+) and the chromate anion (CrO4)2-.Pb4+ + 2(CrO4)2- --> Pb(CrO4)2
The chemical symbol for chromate is CrO4^2-.
The symbol for a chromate ion is CrO4^2-.
The solubility product expression for silver chromate (Ag2CrO4) is Ksp = [Ag+]²[CrO4²-], where [Ag+] represents the concentration of silver ions and [CrO4²-] represents the concentration of chromate ions in the saturated solution.
2Ag(aq)+ CrO4(s)---->AgCrO4(s)
The Ksp expression for silver chromate (Ag2CrO4) is: Ksp = [Ag+]^2 * [CrO4^2-]
Two types: silver (Ag+) and chromate (CrO4-2) And within the formula (Ag2CrO4) there are two silver ions and one chromate ion for a total of three ions.
the Molecular equation would be AgNO3 + Na2CrO4 =yields= Ag2CrO4 + NaNO3 On the product side the silver cromate is insoluble, therefore it will form a precipitate remember everything is aquous (aq) except the silver cromate it is solid (s) Net Ionic equation is Ag(aq) + CrO4 -2 (aq) > Ag2CrO4(s)
No. It is an ionic compound composed of the lead IV cation (Pb4+) and the chromate anion (CrO4)2-.Pb4+ + 2(CrO4)2- --> Pb(CrO4)2
Silver Chromate Ag=Silver CrO4= Chromate(a polyatomic ion)
The chemical symbol for chromate is CrO4^2-.
The symbol for a chromate ion is CrO4^2-.
Formula: CrO4-2
The name of the ionic compound K2(CrO4) is potassium chromate.
insoluble