That is,
Ag2CrO4
Ag + and CrO4 2-
come together to form Ag2CrO4
Silver chromate
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The Ksp expression for silver chromate (Ag2CrO4) is: Ksp = [Ag+]^2 * [CrO4^2-]
Two types: silver (Ag+) and chromate (CrO4-2) And within the formula (Ag2CrO4) there are two silver ions and one chromate ion for a total of three ions.
No. It is an ionic compound composed of the lead IV cation (Pb4+) and the chromate anion (CrO4)2-.Pb4+ + 2(CrO4)2- --> Pb(CrO4)2
The chemical symbol for chromate is CrO4^2-.
The symbol for a chromate ion is CrO4^2-.
The solubility product expression for silver chromate (Ag2CrO4) is Ksp = [Ag+]²[CrO4²-], where [Ag+] represents the concentration of silver ions and [CrO4²-] represents the concentration of chromate ions in the saturated solution.
2Ag(aq)+ CrO4(s)---->AgCrO4(s)
The Ksp expression for silver chromate (Ag2CrO4) is: Ksp = [Ag+]^2 * [CrO4^2-]
Two types: silver (Ag+) and chromate (CrO4-2) And within the formula (Ag2CrO4) there are two silver ions and one chromate ion for a total of three ions.
the Molecular equation would be AgNO3 + Na2CrO4 =yields= Ag2CrO4 + NaNO3 On the product side the silver cromate is insoluble, therefore it will form a precipitate remember everything is aquous (aq) except the silver cromate it is solid (s) Net Ionic equation is Ag(aq) + CrO4 -2 (aq) > Ag2CrO4(s)
No. It is an ionic compound composed of the lead IV cation (Pb4+) and the chromate anion (CrO4)2-.Pb4+ + 2(CrO4)2- --> Pb(CrO4)2
Silver Chromate Ag=Silver CrO4= Chromate(a polyatomic ion)
The chemical symbol for chromate is CrO4^2-.
The symbol for a chromate ion is CrO4^2-.
Formula: CrO4-2
The name of the ionic compound K2(CrO4) is potassium chromate.
The compound AgCrO4 is named silver chromate. It consists of silver (Ag) as the cation, and chromate (CrO4) as the anion. The name is derived from the combination of the names of the two elements involved.