2Ag(aq)+ CrO4(s)---->AgCrO4(s)
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
This equation is: 2 AgNO3 + K2CrO4 => Ag2CrO4 + 2 KNO3.
Silver chloride is 1/10 soluble than silver chromate in the cold 1/3 in hot water. That means silver will incline to precepetate as AgCl preferentially. More over if chromate will form it will convert to silver nitrate.
the chemical reaction between silver nitrate and potassium chromate in generally used in a titration to look for chloride ions , and is a two step reaction: i will give you the ionic equations, which is pretty much all you need Ag+(aq) + Cl-(s) --> AgCl(s) this part of the equation caused the solution to go cloudy. when all the chloride ions are used up then the silver reacts with the chromate ions to produce the red colour you see when the end point of the precipitation is reached: 2Ag+(aq) + CrO4 2-(aq) --> Ag2 CrO4(s) which produces the red colour the amount of silver nitrate relates directly to the chloride ion concentration as it is a 1:1 ration reaction. i hope this answers your question =)
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
how many moles are there in 56.0 grams of silver nitrate?
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
Potassium nitrate is too stable and so is silver for these two species to react. There is thus no balanced equation.
Silver chromate is not soluble in water.
This equation is: 2 AgNO3 + K2CrO4 => Ag2CrO4 + 2 KNO3.
The chemical equation is: 2 K+ + (CrO4)2-(aq) + 2 Ag+ + 2 [NO3]-(aq) --> Ag2CrO4(s) + 2 K+ + 2 [NO3]-(aq)
Silver chloride is 1/10 soluble than silver chromate in the cold 1/3 in hot water. That means silver will incline to precepetate as AgCl preferentially. More over if chromate will form it will convert to silver nitrate.
no
Potassium nitrate and a precipitate of Silver iodide are formed
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3