FeSO4
1 to 1
The whole number mole ratio of calcium sulfate (CaSO4) to water (H2O) in the compound CaSO4·2H2O is 1:2. This means that for every one mole of calcium sulfate, there are two moles of water present.
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
The simplest formula based on the given moles would be BaSO4 (barium sulfate). This is determined by dividing each mole value by the smallest mole value (0.080 mole), resulting in a ratio of 1 Ba : 1 S : 4 O, which corresponds to BaSO4.
In iron (III) sulfate, the ratio of iron to sulfate ions is 1:2. This means that for every one mole of iron (III) sulfate, there are three moles of sulfate ions. To find the number of sulfate ions in a 375.0 gram sample of iron (III) sulfate, you would first calculate the number of moles of iron (III) sulfate, and then multiply that by three to find the number of sulfate ions.
The mole ratio would be 1:1. For example, if you have 1 mole of chromite, you will also have 1 mole of ferrochrome when it is completely converted.
Since both barium chloride and barium sulfate contain one mole of barium atoms pert mole of compound, the moles of barium sulfate will be the same, 0.100, when barium has the limiting concentration in the production of the sulfate.
The molar mass of sulfate is 96.06 g/mol. Therefore, one mole of sulfate contains 96.06 grams of sulfate.
No. According to the law of definite proportions, the mole ratio will always be the same.
If the moles of Fe2O3 are known, you would use the mole ratio from the balanced chemical equation for the reaction involving Fe2O3 and Fe. In the balanced equation, the mole ratio between Fe2O3 and Fe is 2:2, which simplifies to 1:1. This means that for every mole of Fe2O3, there is an equivalent mole of Fe.
To determine the limiting reactant, we need to compare the moles of each reactant. First, calculate the moles of aluminum and copper sulfate separately. Then, determine the mole ratio between them and see which reactant is present in lower amount compared to the stoichiometric ratio. The reactant that is present in lower moles is the limiting reactant.
To find the amount of aluminum needed to produce aluminum sulfate, you need to consider the molar mass of aluminum sulfate and the ratio of aluminum in the compound. First, calculate the molar mass of aluminum sulfate (Al2(SO4)3). Then, find the ratio of aluminum in the compound (2 moles of Al in 1 mole of Al2(SO4)3). Finally, use this information to calculate the grams of aluminum needed to produce 25.0 grams of aluminum sulfate.
No, the mole ratio from a balanced chemical equation cannot be directly interpreted as a ratio of masses. The mole ratio represents the ratio of moles of one substance to another in a chemical reaction, whereas the ratio of masses would depend on the molar masses of the substances involved. However, if you know the molar masses of the substances, you can convert between moles and masses using this information.