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How many moles of fe3o4 are needed to prepare 4.05moles of fe2o3?
To find the moles of Fe3O4 needed, we first need to determine the molar ratio between Fe3O4 and Fe2O3. The balanced chemical equation for the conversion will provide this information. If the equation is Fe3O4 -> 2Fe2O3, then the molar ratio is 1:2. Thus, 4.05 moles of Fe2O3 would require 2 * 4.05 = 8.1 moles of Fe3O4.
The formula for rust can be represented by Fe2O3 How many moles of Fe are present in 14.2 g of the compound?
To find the number of moles of Fe in 14.2 g of Fe2O3, we need to use the molar mass of Fe2O3 (molecular weight = 159.69 g/mol) and the ratio of Fe to Fe2O3. There are 2 moles of Fe in 1 mole of Fe2O3, so we find the moles of Fe in 14.2 g of Fe2O3 by: (14.2 g / 159.69 g/mol) * 2 = 0.249 moles of Fe.
How many grams of C are required to react with 2.50 moles of Fe2O3?
To determine the grams of carbon needed to react with 2.50 moles of Fe2O3, you first need to balance the equation for the reaction between C and Fe2O3. Then, calculate the molar ratio between C and Fe2O3 from the balanced equation. Finally, use the molar mass of carbon to convert the moles of carbon to grams.
If 4.00 kg of Fe2O3 are available to react how many moles of CO are needed and how many moles of each product are formed?
mass / molar mass molar mass Fe2O3 = 159.69 g/mol mass Fe2)3 = 4.00 kg = 4000 g moles = 4000 g / 159.69 g/mol = 25.05 moles Fe2O3 The balanced equation tells you that 1 mole Fe2O3 requires 3 moles CO to react So 25.05 moles needs (3 x 25.05) moles CO = 75.15 moles Co is needed to react 4.00 kg Fe2O3 = 75.2 mol (3 sig figs) b) The equation tells you that 1 moles Fe2O3 reacts to form 2 moles Fe So 25.05 moles will form (2 x 25.05) mol Fe moles Fe formed = 50.10 moles = 50.1 mol (3 sig figs) The equation tells you 1 mole Fe2O3 reacts to form 3 moles CO2 So 25.05 mol Fe2O3 will form (3 x 25.05) mol CO2 = 75.15 moles CO2 = 75.2 mol (3 sig figs) ==
How many grams of oxygen are needed to react with 350 grams of iron to produce 500 grams of fe203?
The balanced chemical equation for the reaction between iron and oxygen to produce Fe2O3 is 4Fe + 3O2 -> 2Fe2O3. From the equation, we see that 3 moles of oxygen react with 4 moles of iron to produce 2 moles of Fe2O3. Therefore, to find the grams of oxygen needed, we need to calculate the molar mass of Fe2O3 and then determine the number of grams needed using the mole ratio from the balanced equation.
How many moles of fe3o4 are needed to prepare 4.05moles of fe2o3?
To find the moles of Fe3O4 needed, we first need to determine the molar ratio between Fe3O4 and Fe2O3. The balanced chemical equation for the conversion will provide this information. If the equation is Fe3O4 -> 2Fe2O3, then the molar ratio is 1:2. Thus, 4.05 moles of Fe2O3 would require 2 * 4.05 = 8.1 moles of Fe3O4.
The formula for rust can be represented by Fe2O3 How many moles of Fe are present in 14.2 g of the compound?
To find the number of moles of Fe in 14.2 g of Fe2O3, we need to use the molar mass of Fe2O3 (molecular weight = 159.69 g/mol) and the ratio of Fe to Fe2O3. There are 2 moles of Fe in 1 mole of Fe2O3, so we find the moles of Fe in 14.2 g of Fe2O3 by: (14.2 g / 159.69 g/mol) * 2 = 0.249 moles of Fe.
How many grams of C are required to react with 2.50 moles of Fe2O3?
To determine the grams of carbon needed to react with 2.50 moles of Fe2O3, you first need to balance the equation for the reaction between C and Fe2O3. Then, calculate the molar ratio between C and Fe2O3 from the balanced equation. Finally, use the molar mass of carbon to convert the moles of carbon to grams.
If 4.00 kg of Fe2O3 are available to react how many moles of CO are needed and how many moles of each product are formed?
mass / molar mass molar mass Fe2O3 = 159.69 g/mol mass Fe2)3 = 4.00 kg = 4000 g moles = 4000 g / 159.69 g/mol = 25.05 moles Fe2O3 The balanced equation tells you that 1 mole Fe2O3 requires 3 moles CO to react So 25.05 moles needs (3 x 25.05) moles CO = 75.15 moles Co is needed to react 4.00 kg Fe2O3 = 75.2 mol (3 sig figs) b) The equation tells you that 1 moles Fe2O3 reacts to form 2 moles Fe So 25.05 moles will form (2 x 25.05) mol Fe moles Fe formed = 50.10 moles = 50.1 mol (3 sig figs) The equation tells you 1 mole Fe2O3 reacts to form 3 moles CO2 So 25.05 mol Fe2O3 will form (3 x 25.05) mol CO2 = 75.15 moles CO2 = 75.2 mol (3 sig figs) ==
How can one determine the ratio of moles in a chemical reaction?
To determine the ratio of moles in a chemical reaction, you can use the coefficients of the balanced chemical equation. The coefficients represent the number of moles of each substance involved in the reaction. By comparing the coefficients of the reactants and products, you can determine the mole ratio between them.
How many grams of oxygen are needed to react with 350 grams of iron to produce 500 grams of fe203?
The balanced chemical equation for the reaction between iron and oxygen to produce Fe2O3 is 4Fe + 3O2 -> 2Fe2O3. From the equation, we see that 3 moles of oxygen react with 4 moles of iron to produce 2 moles of Fe2O3. Therefore, to find the grams of oxygen needed, we need to calculate the molar mass of Fe2O3 and then determine the number of grams needed using the mole ratio from the balanced equation.
If 1.00 kg of Fe2O3 completely reacts with CO the volume of CO2 released at STP will be?
There are several different possible reactions of Fe2O3 with CO, depending on temperature and ratio of reactants. The simplest is probably Fe2O3 + CO ==>2FeO + CO21.00 Kg x 1000 g/Kg x 1 mole Fe2O3/160 g = 6.25 moles Fe2O3 moles CO2 produced = 6.25 moles CO2 Volume CO2 at STP = 6.25 moles x 22.4 L/mole = 140 Liters
How many grams of Fe2O3 are formed when 16.7g of Fe reacts completely with oxygen?
The rusting of iron has the reaction 4 Fe + 3 O2 equals 2 Fe2O3. So every 2 moles of iron produces 1 moles of iron oxide. 16.7 grams is .299 moles of iron. This means there are 0.149 moles of iron oxide or 23.88 grams.
How can one determine the empirical formula from moles in a chemical compound?
To determine the empirical formula from moles in a chemical compound, you first need to find the moles of each element present in the compound. Then, divide the moles of each element by the smallest number of moles to get the simplest whole number ratio. This ratio represents the empirical formula of the compound.
Identify the number of moles of excess reagent left over when 8.368 moles of iron III oxide are reacted with 9.825 moles of aluminum in the thermite reaction.?
To find the excess reagent, first write and balance the chemical equation for the thermite reaction: 2Al + Fe2O3 -> 2Fe + Al2O3 Next, determine the limiting reagent using the mole ratios (in this case, Fe2O3 is limiting). Then, calculate the moles of excess reagent left over (Al) using the mole ratio from the balanced equation. Subtract the moles of Al consumed from the initial moles of Al to find the excess.
Analysis of a compound composed of iron and oxygen yields 174.86 g Fe and 75.14 g O What is the empirical formula for this compound?
The first step is to convert the masses of Fe and O into moles: 174.86 g Fe is 3.13 moles of Fe, and 75.14 g O is 4.69 moles of O. The ratio of Fe to O in the compound is approximately 2:3. Therefore, the empirical formula of the compound is Fe2O3, which is iron(III) oxide (also known as rust).
Iron III oxide is formed when iron combines with oxygen in the air How many grams of Fe2O3 are formed when 16.7 g of Fe reacts completely with oxygen?
To determine the mass of Fe2O3 formed, you need to first find the molar mass of Fe and Fe2O3. Then, use stoichiometry to calculate the mass of Fe2O3 that can be produced from 16.7 g of Fe. The balanced equation is 4Fe + 3O2 → 2Fe2O3, which shows that 4 mol of Fe produces 2 mol of Fe2O3. By converting 16.7 g of Fe to moles, you can then use the mole ratio to find the grams of Fe2O3 formed.
