Sodium fluoride.
Lithium. Practically every metal combined with fluorine will give you an ionic compound. Some transition metals have volatile penta and hexafluorides and these are bonded with polar covalent bonds.
8
water,carbon-dioxide,glucose,sodium chloride,iron sulphide,lead chloride,sulphur dioxide
Cillit Bang.
google, elgoog, and google
Lithium. Practically every metal combined with fluorine will give you an ionic compound. Some transition metals have volatile penta and hexafluorides and these are bonded with polar covalent bonds.
Sodium chloride is a polar compound as water.
Bright yellow :: This is the sodium ions. Any sodium compound will give a flame test colour of yellow/
Many elements can form an ionic bond with fluorine. Metals in groups one and two (such as alkali metals lithium, sodium, potassium, etc. or alkali earth metals like magnesium or calcium) like to form ionic compounds with fluorine. This is because fluorine has an extra electron it wants to give away, and metals in group one and two want another electron to become stable.
No. There is no carbon in either sodium sulphate or hydrochloric acid so they cannot produce a compound containing carbon.
Because in a Belstein test, the copper halide should be able to volatilize to produce green flame, an indication that a halogen is present in the compound. Copper fluoride is not volatile., hence this kind of test is not suitable for the detection of fluorine.
Salinity (or 'saltiness') is due to the compound sodium chloride, written NaCl, and adding more of this will increase the salinity. However never add metallic sodium to water, it produces a violent and dangerous reaction. So when you say 'adding sodium to chloride' I'm not sure what you mean. The compound sodium chloride is just cooking salt and quite harmless and you can add as much of that as you like, but sodium as an element is a different matter.
8
water,carbon-dioxide,glucose,sodium chloride,iron sulphide,lead chloride,sulphur dioxide
Cillit Bang.
google, elgoog, and google
Sodium oxide is Na2O and not NaO, because it has 2 elements of sodium (Na). therefore making it Na2O instead of NaOThe reason why it's Na2O and not NaO is because Oxygen whilst in a compound has an oxidation state of2-, while Sodium has an oxidation state of 1+. Therefore to give an overall value of 0 to the compound, you need two Sodium atoms joined to only one Oxygen atom.