Hey there. To answer this accurately, i would need to know the genotypes of both parents. I'll show you a trick that works them out in a flash.
A phenotype is the result of a genotype, which is the result of 2 alleles. Say if both parents were HOMOZYGOUS for brown hair, with their genotype would be BB, BB. Use a trick called a punnet square to answer this;
_|B |B |
B|BB|BB| <-- not the best punnet square, but the top row shows the first parents
B|BB|BB| genotype (BB) and the side shows the second's. (BB) The cross of this
shows all the children will have brown hair, as inherited from each parent.
If the Mother had HOMOZYGOUS brown hair (BB), and the father had HETEROZYGOUS brown hair (Bb) the results would be 100% Brown hair too, because the brown hair gene (B) is dominant over the non brown hair gene (b). Below;
_|B |B |
B|BB|BB| <--- this shows the cross gives a 50% chance to be Homozygous for brown
b|Bb|Bb| hair but 50% heterozygous for brown hair, but carrying a non- brown hair
gene.
If we cross 2 heterozygous parents, the results are shown:
_|B |b |
B|BB|Bb|
b|bB|bb| <----- This shows the child has a 75% chance of having brown hair (either
(BB or bB, Bb) and 25% of being non-brown (bb)).
This can be used in any gene cross, but you must keep in mind that one gene will be dominant and one will be recessive. I used the brown hair gene as an example here, as I don't know whether it may be dominant or recessive to other hair colours.
Also, if you were after a global statistic, I wouldn't know. I hope this helps you.
Fletch
It depends first of the genotype of the parents and the type of heredity. If both parents are homozygous dominant or recessive then the offspring will be the same genotype and phenotype (100%). Through normal heredity if both parents are heterozygous then the chances of the offspring having the same phenotype is 75% to 25%.
25%
The percentage of the possible types of offspring that had the same phenotype as the parents are : bB-bb,BB-Bb=25% has black hair (dad) and 75% has blonde hair (mom).
75 percent
75%
75%
What percentage of the possible types of offspring had the same phenotype as the parents
Genotype is the coded for traitPhenotype is the visible characteristicSo in the case where both parents had heterozygous dominant Brown eyes (Bb - big B for brown, dominant gene; little b for blue recessive gene); it is possible for the child to have blue eyes, by being homozygous recessive (bb).However this is an educated guess, as your question does not make sense.
The blending of the phenotype of the parents in the offspring is known as incomplete. colors of flowers can show incomplete dominance if a red flower is crossed with a white flower and their offspring are pink.
Don't give us the options then!! If one parent had 2 dominant genes then all offspring would have dominant phenotype, the same goes for both parents having dominant genes.
My Nan.
What percentage of the possible types of offspring had the same phenotype as the parents
What percentage of the possible types of offspring had the same phenotype as the parents
25% The percentage of the possible types of offspring that had the same phenotype as the parents are : bB-bb,BB-Bb=25% has black hair (dad) and 75% has blonde hair (mom).
75%
If both parents have the same phenotype, but the offspring did not share that phenotype, then it is likely that the parents have a dominant phenotype, but the offspring has a recessive phenotype, which means that the offpring's genotype would be homozygous recessive, and it's parents' genotypes would be heterozygous. For example, the parents may both have the genotype Bb, which gives them black fur. Approximately 25% of their offspring should have the genotype bb, which gives them the phenotype of white fur.
If both parents have the same phenotype, but the offspring did not share that phenotype, then it is likely that the parents have a dominant phenotype, but the offspring has a recessive phenotype, which means that the offpring's genotype would be homozygous recessive, and it's parents' genotypes would be heterozygous. For example, the parents may both have the genotype Bb, which gives them black fur. Approximately 25% of their offspring should have the genotype bb, which gives them the phenotype of white fur.
Genotype is the coded for traitPhenotype is the visible characteristicSo in the case where both parents had heterozygous dominant Brown eyes (Bb - big B for brown, dominant gene; little b for blue recessive gene); it is possible for the child to have blue eyes, by being homozygous recessive (bb).However this is an educated guess, as your question does not make sense.
The genotype of the offspring that had the same phenotype as the parents is rr or wrinkled. The phenotype for the seed shape of both parent plants is round.
Question needs more detail..... F1 offspring are the first generation of children from a specific set of parents. Their genotype/phenotype would depend on that of the parents.
The blending of the phenotype of the parents in the offspring is known as incomplete. colors of flowers can show incomplete dominance if a red flower is crossed with a white flower and their offspring are pink.
No. Parents with the dominant phenotype might be heterozygous in their genotype. This means they could carry both the dominant and recessive allele for a trait. So they could both pass the recessive allele to an offspring, who would then have the homozygous recessive genotype and recessive phenotype.
Question needs more detail..... F1 offspring are the first generation of children from a specific set of parents. Their genotype/phenotype would depend on that of the parents.