Saturn.
The value of the gravitational field strength on a planet with half the mass and half the radius of Earth would be the same as Earth's gravitational field strength. This is because the gravitational field strength depends only on the mass of the planet and the distance from the center, not on the size or density of the planet.
The gravitational force from a planet on the sun is so small. For example, 1,000,000 Earths can fit in the sun. The mass of the sun is 333,000 times bigger than the Earth. It is the same way you on Earth. You have a gravitational force on the Earth but it is so small.
it's almost the same ... but earth's is a little bit more
Planet Earth.
If a planet has twice the mass of Earth and its radius is increased by a factor of 2, the gravitational field strength at its surface can be calculated using the formula ( g = \frac{GM}{R^2} ). Here, ( G ) is the gravitational constant, ( M ) is the mass, and ( R ) is the radius. By doubling the radius while doubling the mass, the gravitational field strength becomes ( g' = \frac{2G(2M_E)}{(2R_E)^2} = \frac{G M_E}{R_E^2} ), which equals Earth's gravitational field strength. Thus, the conditions for gravitational strength to be the same as on Earth are satisfied.
Jupiter, its more massive.
If the planet is smaller, then it can't have the same size. If you assume that a smaller planet has the same density as Earth (and therefore less mass), its surface gravity will be smaller. If you assume that a smaller planet has the same mass as Earth (and therefore more density), its surface gravity will be greater. This is because we would be closer to the planet's center - or to the planet's matter in general.
NO. They all have gravity.
If a planet has twice the mass of Earth, its radius would need to be larger than Earth's to maintain the same gravitational field strength at its surface. Specifically, to achieve equivalent gravitational acceleration, the radius must increase by a factor of about 1.414 (the square root of 2), not 2. This is because gravitational field strength is directly proportional to mass and inversely proportional to the square of the radius (g = G * M / r²). Therefore, a radius larger by a factor of 2 would actually result in a lower gravitational field strength than that of Earth.
For a planet to have the same gravitational field strength at its surface as Earth while having twice its mass, its radius must increase. The gravitational field strength ( g ) is given by the formula ( g = \frac{G \cdot M}{R^2} ), where ( G ) is the gravitational constant, ( M ) is mass, and ( R ) is radius. If the mass ( M ) is doubled, to maintain the same gravitational field strength ( g ), the radius ( R ) must be increased by a factor of ( \sqrt{2} ), not 2. Therefore, the radius would need to be larger by a factor of approximately 1.414.
i dont now
no planet