answer is 2 lamps...
For 200w/220v
p1=v*i1
200=220*i1
we get i1=10/11
v=i1*r1
220=(10/11)*r1
r1=242 ohms --------------1
For 100w/220v
p2=v*i2
100=220*i2
we get i2=5/11
v=i2*r2
200=(5/11)*r2
r2=484 ohms----------------2
As n no of 200w/220v lamp is connected in series should consume the same power as that of single 100w/220v lamp ....
(v^2/n*r1)=(v^2/n*r2)-----------------3
substituting 1 and 2 in 3 ,we get..
n=2
hope am right...if not correct me...
ANSWER
Unfortunately, you are wrong.
As the resistance of each lamp filament is temperature dependent (a hot lamp has up to 18 times its cold resistance!) , there is no way of determining the resistance of each lamp when subjected to a voltage other than its rated voltage because we don't know the operating temperature at the reduced voltage. So there's no way of calculating the resulting power of each lamp when connected in series and subject to half its rated voltage. So this question cannot be answered.
if you don't know the answer to this question you should not mess with 440...but the answer is no!!! 440 VAC CAN KILL YOU if you screw up, don't use any product with arating or insulation threshold of less than 440 with a 440 circuit. the voltage can arc , and cross phases, causing injury or death...
If the 100 watt bulbs were intended to run on 110 volts, then the power used by the 100 watt bulbs in series on 220 volts is 200 watts. If the bulbs were intended to run on 220, then the power is about 50 watts, or 25 watts each, but since the bulbs will be running at a lower temperature the power will be slightly higher than expected. This use of series bulbs is not consistent with US NEC. Replacing one bulb could cause personal contact with 220 volts in what would be expected to be a 110 volt application. Check your applicable codes.
If the bulbs are rated for 110 volts and 100W, then the power consumed by a single light bulb at 220 volts (double the normal voltage) will be (2^2) times it's normal power usage - 400 watts per bulb, or 800 total. Power = voltage squared divided by resistance.
if these are 220 volt, 100W bulbs, they will use 200 watts total.
if bulbs are resistive then the formula is v=IR
V- Voltage
I- Current
R- Resistance
suppose if voltage is 215 V (as in India)
Then apply P= VI to find I
P- Power
100W = 215* I
I = 0.465 Amps
Now, V = IR
230= 0.465 * R
R = 494.62 Ohm
resistance for 10 Bulbs of 100W (Resistances are additive in series)
= 494.62 x 120
= 4946.2 Ohm
= 4.946 Kilo Ohm
Got it, and you can also find this knowing the material used in bulb manufacturing
using R = (Ro x L)/A
Ro - resistivity of the material
L - Length
A - Area
Two equal bulbs in parallel will use twice the current and twice the power.
The battery should be 4.5 v which is three 1.5 v cells in series. The power in watts depends on the size of the bulbs.
Change the trailer light bulbs to 24 volts and supply a 24 volt source to power them, in that order.
Connecting batteries + to - is said to be connecting them in series. The voltage from two batteries in series will be additave. So two 1.5 volt batteries in series will give you 3.0 volts.
Any devices using 240 volts up to 8 amp and any devices using 120 volts up to 16 amps.
Volts isn't power. Volts times amps is power, also known as watts. Thus 480 volts at 2 amps consumes 960 watts, which is the same power usage of 240 volts at 4 amps or 120 volts at 8 Amps.
The battery should be 4.5 v which is three 1.5 v cells in series. The power in watts depends on the size of the bulbs.
Since the bulbs are in series, each one will have 40 volts across it instead of the 120 volts it was designed for. The bulbs will glow very dimly or not at all.
In the parallel connection the voltage is same across both lampsFor example 2 bulbs rated at 10 Volts and drawing 1 amp each will consume 20 Watts of power and burn with full brilliance.In the series connection the 2 bulbs can only have 5 Volts across each bulb. The current can only be 0.5 Amps and the power drawn from the supply is now 2.5Watts in each bulb. The two dim bulbs only draw a total of 5 Watts.
If the bulbs are wired in series, the voltage rating for each bulb is the source voltage divided by the number of bulbs in the series. You can tell if they're wired in series by removing a bulb. If all of the other lights go out, you have a series circuit. If all of the other bulbs stay lit, you have a parallel circuit. If half of the lights go out and the other half stay lit, you have two series circuits in parallel. The source voltage is about 110 volts in North America or about 220 volts in Europe (I don't know about Asia or Australia). If you have a series/ parallel mix, count only the bulbs that go out with the one you removed. For example, if you have 50 lights in one series in North America, the voltage across each bulb is about 2.2 volts.
If you put the 25w behind the 100w then it might not work at the full 25w and vice versa
If it is in the same circuit, the voltage would not be the same. ANSWER: That is possible if both bulbs have the same rating of volts and amperes
Change the trailer light bulbs to 24 volts and supply a 24 volt source to power them, in that order.
The maximum voltage of incandescent light bulbs is up to about three hundred volts. They can also go down as low as 1.5 volts. Incandescent light bulbs are the least efficient lighting system. More modern methods like flourescent lightbulbs are far more efficient.
Connecting batteries + to - is said to be connecting them in series. The voltage from two batteries in series will be additave. So two 1.5 volt batteries in series will give you 3.0 volts.
As many as you want. But where do you find 640 volts RMS?
Any devices using 240 volts up to 8 amp and any devices using 120 volts up to 16 amps.
Most car batteries are 12 volts. They can light 12 volt bulbs. The bulbs in your house are likely 120 volt bulbs. A car battery will not light those without some very special equipment, or unless you were to wire ten car batteries in series.