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answer is 2 lamps...

For 200w/220v

p1=v*i1

200=220*i1

we get i1=10/11

v=i1*r1

220=(10/11)*r1

r1=242 ohms --------------1

For 100w/220v

p2=v*i2

100=220*i2

we get i2=5/11

v=i2*r2

200=(5/11)*r2

r2=484 ohms----------------2

As n no of 200w/220v lamp is connected in series should consume the same power as that of single 100w/220v lamp ....

(v^2/n*r1)=(v^2/n*r2)-----------------3

substituting 1 and 2 in 3 ,we get..

n=2

hope am right...if not correct me...

ANSWER

Unfortunately, you are wrong.

As the resistance of each lamp filament is temperature dependent (a hot lamp has up to 18 times its cold resistance!) , there is no way of determining the resistance of each lamp when subjected to a voltage other than its rated voltage because we don't know the operating temperature at the reduced voltage. So there's no way of calculating the resulting power of each lamp when connected in series and subject to half its rated voltage. So this question cannot be answered.

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9y ago
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14y ago

if you don't know the answer to this question you should not mess with 440...but the answer is no!!! 440 VAC CAN KILL YOU if you screw up, don't use any product with arating or insulation threshold of less than 440 with a 440 circuit. the voltage can arc , and cross phases, causing injury or death...

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14y ago

If the 100 watt bulbs were intended to run on 110 volts, then the power used by the 100 watt bulbs in series on 220 volts is 200 watts. If the bulbs were intended to run on 220, then the power is about 50 watts, or 25 watts each, but since the bulbs will be running at a lower temperature the power will be slightly higher than expected. This use of series bulbs is not consistent with US NEC. Replacing one bulb could cause personal contact with 220 volts in what would be expected to be a 110 volt application. Check your applicable codes.

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13y ago

If the bulbs are rated for 110 volts and 100W, then the power consumed by a single light bulb at 220 volts (double the normal voltage) will be (2^2) times it's normal power usage - 400 watts per bulb, or 800 total. Power = voltage squared divided by resistance.

if these are 220 volt, 100W bulbs, they will use 200 watts total.

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12y ago

if bulbs are resistive then the formula is v=IR

V- Voltage

I- Current

R- Resistance

suppose if voltage is 215 V (as in India)

Then apply P= VI to find I

P- Power

100W = 215* I

I = 0.465 Amps

Now, V = IR

230= 0.465 * R

R = 494.62 Ohm

resistance for 10 Bulbs of 100W (Resistances are additive in series)

= 494.62 x 120

= 4946.2 Ohm

= 4.946 Kilo Ohm

Got it, and you can also find this knowing the material used in bulb manufacturing

using R = (Ro x L)/A

Ro - resistivity of the material

L - Length

A - Area

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10y ago

Two equal bulbs in parallel will use twice the current and twice the power.

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Q: What power is used by two 100 watts bulbs with 220 volts connecting in series?
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