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What quantities are zero throughout the flight of a projectile?
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What is the vertical speed of a projectile at the top of its flight?
Zero.
How Does Projectile differ from a object in free fall?
The initial velocty of a projectile is non-zero.
Which is the total velocity of a projectile at maximum height?
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
What quantities remain constant in projectile motion?
All that I can think of are: 1.) Gravity 2.) Wind 2.A) wind speed 2.B) direction of wind 3.) Angle of trajectory 4.) Initial speed of projectile 5.) Material through which projectile travels (as in density) 6.) Mass of projectile 7.) Spin 7.A) speed of spin 7.B) axis/axes spining occurs on 8.) Shape of projectile 9.) Temperature of medium projectile is in 10.) Size of projectile (as in height, width, and depth) 11.) Weighting of projectile 12.) Obsturctions to projectile's path In a vaccuum, though, these are the variables: 1.) Speed of object 2.) Obstructions in path 3.) Gravity
How can you throw a projectile so that it has zero speed at the top?
Throw it with zero horizontal speed, i.e. straight up. (Remember to move out of the way.)
What is the vertical speed of a projectile at the top of its flight?
Zero.
How Does Projectile differ from a object in free fall?
The initial velocty of a projectile is non-zero.
Which is the total velocity of a projectile at maximum height?
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
Ignoring air resistance what is the horizontal component of a projectile's acceleration?
Zero.
What quantities remain constant in projectile motion?
All that I can think of are: 1.) Gravity 2.) Wind 2.A) wind speed 2.B) direction of wind 3.) Angle of trajectory 4.) Initial speed of projectile 5.) Material through which projectile travels (as in density) 6.) Mass of projectile 7.) Spin 7.A) speed of spin 7.B) axis/axes spining occurs on 8.) Shape of projectile 9.) Temperature of medium projectile is in 10.) Size of projectile (as in height, width, and depth) 11.) Weighting of projectile 12.) Obsturctions to projectile's path In a vaccuum, though, these are the variables: 1.) Speed of object 2.) Obstructions in path 3.) Gravity
How can you throw a projectile so that it has zero speed at the top?
Throw it with zero horizontal speed, i.e. straight up. (Remember to move out of the way.)
What is the acceleration of a projectile when instantaneous vertical velocity is zero at the top of its projectile?
Acceleration at the point of zero vertical velocity will be equivalent to gravitational acceleration on that body. On Earth, for example, this is around 9.8 meters per second per second (9.8m/s2).
How can you throw a projectile so that it has nonzero speed at the top of trajectory?
If the projectile's velocity has a horizontal component - in other words, it doesn't go straight up - then its speed will never be zero.
What makes two quantities proportional?
Any two non-zero quantities are always proportional. If the two quantities are X and Y, they are proportional to X/Y.
What is the vertical acceleration of a projectile if the vertical component of its velocity vector is zero?
The vertical component of a projectile's velocity is irrelevant. It can be up, down, or zero, makes no difference. As long as projectile motion lasts ... gravity is the only force on the object and you're ignoring air resistance ... its acceleration is constant, and is equal to the acceleration of gravity: 9.8 meters per second2 pointing down.
A projectile fired from the ground follows a parabolic path The speed of the projectile is minimum at the top of its path?
Yep that is correct. To understand this it may help you to draw a parabola. If you draw a line from the top of the parabola back to the ground you'd notice either side of this line is symmetrical. This isn't quite what happens to a projectile (following a parabolic path), but because of the nature of the question, effects such as air resistance can be ignored. As the projectile approaches the top of its path, the vertical component of its velocity approaches zero. As the projectile begins to fall the magnitude of the vertical component of the projectile begins to increase. The only force that acts on the projectile during flight is gravity which pulls it towards the earth. Since this force and the horizontal component of the projectiles velocity are at right angles to each other, the horizontal component of the velocity is unaffected during flight . This explains the symmetry of the parabola and also means the time to reach the top of path equals the time from the top of path back to the ground. The projectile will hit the ground with the same speed as it left the ground. If you draw a horizontal line through the parabola, at the two points where the line and the parabola cross, the speed of the projectile will be the same. The only change to the balls speed during the flight comes as the vertical component of its velocity tends to zero as it reaches the top of the curve and then falling back down due to gravity. I'm unsure of your physics knowledge but hopefully this doesn't confuse you. If you have learned about vectors, then this can be simply understood/explained.
What is the magnitude of the velocity of a vertical projectile at its maximum height is equal to?
The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.
