At the highest point of its trajectory, the speed of a projectile is equal to zero as it momentarily stops before starting to descend.
The vertical speed at the highest point of a projectile's trajectory is zero. This is because at the peak of the trajectory, the projectile momentarily stops ascending and starts descending, resulting in a velocity of zero in the vertical direction.
A projectile has the least speed at its highest point in the trajectory, also known as the apex. At this point, the vertical speed component is zero, while the horizontal speed component remains constant if no air resistance is considered.
Without air friction, the horizontal component of the velocity will be constant. The vertical component of the velocity will be a maximum at the lowest point in its motion and at a minimum at the highest point in its motion. Therefore the minimum is at the highest point in its motion- Potential energy max Kinetic Energy min and the maximum is at its lowest point in the motion- KE is max PE min
Assuming no air resistance, the time it takes for the projectile to return to its starting point is twice the time it takes to reach the highest point of its trajectory. The time to reach the highest point can be calculated using the equation: time = initial velocity / acceleration due to gravity. Therefore, the total time for the projectile to return would be around 6 seconds.
The vertical velocity of a projectile at the lowest point in its trajectory is zero. This occurs because at that point, the projectile has reached the maximum height and is momentarily stationary before it starts descending.
The vertical speed at the highest point of a projectile's trajectory is zero. This is because at the peak of the trajectory, the projectile momentarily stops ascending and starts descending, resulting in a velocity of zero in the vertical direction.
A projectile has the least speed at its highest point in the trajectory, also known as the apex. At this point, the vertical speed component is zero, while the horizontal speed component remains constant if no air resistance is considered.
Without air friction, the horizontal component of the velocity will be constant. The vertical component of the velocity will be a maximum at the lowest point in its motion and at a minimum at the highest point in its motion. Therefore the minimum is at the highest point in its motion- Potential energy max Kinetic Energy min and the maximum is at its lowest point in the motion- KE is max PE min
The projectile have minimum speed when it is in top of prabolic and it have max sped when it is in intial point
Assuming no air resistance, the time it takes for the projectile to return to its starting point is twice the time it takes to reach the highest point of its trajectory. The time to reach the highest point can be calculated using the equation: time = initial velocity / acceleration due to gravity. Therefore, the total time for the projectile to return would be around 6 seconds.
(As usual when working with this subject, we'll assume zero air resistance.)When the projectile is launched, the horizontal component of its velocity is V0cos(A).At its highest point, its vertical speed is zero; all of its speed is horizontal,and equal to the horizontal speed it had coming out of the muzzle.V0/6 = V0cos(A)cos(A) = 1/6A = cos-1(1/6) = 80.4 degrees (rounded)
The vertical velocity of a projectile at the lowest point in its trajectory is zero. This occurs because at that point, the projectile has reached the maximum height and is momentarily stationary before it starts descending.
The speed of the projectile is 974.15 km/h.
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
A projectile has minimum speed at the top of the trajectory.
To have zero speed at the top, you need to throw the projectile with an initial velocity such that it reaches its maximum height at that point. This requires the initial velocity to be exactly equal to the velocity that would be attained due to gravity when the projectile falls from that height. The angle of projection should be such that the vertical component of the initial velocity cancels out the velocity due to gravity.
At the highest point, the speed of the ball is 0 m/s because it momentarily stops before falling back down. The acceleration at the highest point is equal to the acceleration due to gravity (approximately -9.8 m/s^2) acting in the downward direction.