solid
feo3
FeO3 is a non-exsisting iron oxide.Possible oxides of iron are FeO (ferrous oxide) and Fe2O3 (ferric oxide) and all kind of 'mixtures' of both (oxydules).
First, this would be an compound, not an element. Second, it does not exist. If it did exist it would be iron VI oxide, but iron cannot reach such a high oxidation state. However, there is Fe2O3, which is iron III oxide.
FeO2= is a ferric ion where FeO3- is a ferrous ion.
FeO3 = 103.845 g/mol Fe = 55.845 g/mol (55.845 g/103.845 g) x 100% = 53.8% Fe in 2FeO3
feo2 feo3 feo4
FeO3 is a compound because it is a chemical substance composed of a fixed ratio of iron (Fe) and oxygen (O) atoms in a specific arrangement. Mixtures, on the other hand, consist of two or more substances physically combined without chemical bonding.
Fe3O4 is actually a combination of two compounds, Fe2O3 and FeO. The first is called ferric oxide and the second is ferrous oxide. Fe3o4 is also called fericc fero oxide.
Any Ferrous mineral is made completely up of Iron Oxide of some form. These are Haematite (FeO2) and Magnetite (FeO3). They are very easily identified because they are magnetic and also have a 'Mamellated' habit (rounded - literally breast-like).
Its difficult to understand your question, I can make an assumption (although your stoichiometry is off). Are you asking about Iron Oxide compounds? Iron is a transition metal, abbreviated "Fe." It has two oxidative states, +2 and +3--often written as Fe (II) and Fe (III). If you have Fe(II) oxide, FeO, it would be called "ferrous oxide." If you have Fe(III) oxide, Fe2 O3, it would be called "ferric oxide." The other forms in your question aren't correct and I cannot answer them.
The formula FeO3 is written with 4 atoms: 1x Fe and 3x O, but it is NOT a possible iron oxide formula. However some of the possible iron oxides are: FeO, Fe2O3, Fe3O4 having 2, 5, 7 atoms respectively.
Fe ions =,Fe 2+andFe 3+Oxygen ions =,O 2-So, as you should see, Fe3O4, is an invalid species as the charge on the first iron ion would be 3 * 2+ = 6 +, and the charge on the second iron ion would be 3 * 3+ = 9+. This can not equal 4 * 2- = 8 -.