Fe ions =,
Fe 2+
and
Fe 3+
Oxygen ions =,
O 2-
So, as you should see, Fe3O4, is an invalid species as the charge on the first iron ion would be 3 * 2+ = 6 +, and the charge on the second iron ion would be 3 * 3+ = 9+. This can not equal 4 * 2- = 8 -.
The answer is 2 moles.
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
3 moles of O, so that must be 6 moles of O2
The answer is 0,173 moles.
4.80 grams O2 (1 mole O2/32 grams ) = 0.150 moles of O2
To determine the number of moles of Fe that can be made from 25 moles of Fe2O3, you need to write the balanced chemical equation for producing O2 from Fe2O3. 2Fe2O3 = 4Fe + 3O2, which means that 2 moles of Fe2O3 will produce 4 moles of Fe and 3 moles of O2 . Set up a proportion. 3 moles of O2 ÷ 2 moles of Fe2O3 = x moles of O2 ÷ 25 moles of Fe2O3 Cross multiply and divide. 3 moles of O2 * 25 moles of Fe2O3 ÷ 2 moles of Fe2O3 = 37.5 moles of O2 produced.
First, balance the equation: 4FeS2 + 11O2 → 2Fe2O3 + 8SO2. Calculate the moles of each reactant: moles FeS2 = 1176 g / molar mass of FeS2, moles O2 = 704 g / molar mass of O2. Identify the limiting reactant based on the stoichiometry of the reaction, then use stoichiometry to calculate the grams of Fe2O3 produced.
The answer is 2 moles.
To form iron(III) oxide, the chemical equation is: 4 Fe(s) + 3 O2(g) → 2 Fe2O3(s) From the equation, it can be seen that 3 moles of oxygen (O2) are needed to react with 4 moles of iron (Fe) to produce 2 moles of iron(III) oxide (Fe2O3). The molar mass of oxygen (O2) is approximately 32 g/mol. Therefore, you would need 96 grams of oxygen to react with the iron needed to form iron(III) oxide.
4
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
3 moles of O, so that must be 6 moles of O2
what is ag2o
The answer is 0,173 moles.
15 moles O2 (32 grams/1 mole O2) = 480 grams
For the reaction 2 H2 + O2 -> 2 H2O, we see that 1 mole of O2 produces 2 moles of H2O. Therefore, to produce 10.2 moles of H2O, we would need 5.1 moles of O2.
The balanced chemical equation for the reaction is 2SO2 + O2 -> 2SO3. This means that for every 1 mole of O2 consumed, 2 moles of SO3 are produced. Therefore, 1.32 moles of O2 would produce 2.64 moles of SO3.