H3o+
In this reaction H3O+ is the conjugate acid. The original acid in this reaction is H3PO4
The conjugate acid of any substance is given by removing an acidic hydrogen. In the case of ammonium ion, the conjugate base is ammonia.
NH3 is the conjugate base of NH4+
IN this reaction the conjugate base is the nitrate ion, NO3-
CH3CH3. Wiley Plus confirms this.
In this reaction H3O+ is the conjugate acid. The original acid in this reaction is H3PO4
The conjugate acid of any substance is given by removing an acidic hydrogen. In the case of ammonium ion, the conjugate base is ammonia.
NH3 is the conjugate base of NH4+
IN this reaction the conjugate base is the nitrate ion, NO3-
CH3CH3. Wiley Plus confirms this.
This is a Bronsted question. Hs- is the acid in this which makes H2O a base. Therefore S-2 is the conjugate base and the H3O+ hydronium ion is the conjugate acid.
The reaction of an acid plus a base will result in the formation of a salt plus water.
When a carboxylic acid is added to an alcohol, it forms an ester: Eg: CH3COOH + CH3OH -> CH3COOCH3 Sulphuric acid acts as a catalyst to this reaction Therefore if you add ethanoic acid and sulfuric acid to a unknown substance and it reacts the original substance was an alcohol.
This is an double-displacement reaction, in this case and acid-base reaction.
The ion of a Bronsted-Lowry acid refers to H+, as it is considered to be a "proton donor" by this system. The conjugate base is the anion of the initial acid; e.g., for HCl, Cl- is the conjugate base. To answer the question, a salt is produced when a cation that is not hydrogen joins this conjugate base. Typically speaking, the reaction of an acid and a base yields a salt and water. Let us consider the reaction of hydrobromic acid with potassium hydroxide. HBr + KOH --> HOH + KBr In this case, the salt, potassium bromide, is our expected product. This is all that's meant by the 'different positive atom'.
An acid plus a base will yield a salt and water in a neutralization reaction.
Such as substance is called an acid