Tin (II) fluoride is a compound, with formula SnF2.
Snt2
SnF2
SnF2 is stannous- or tin(II) fluoride
SnF4
First we have to start by determining what charge does Sn have to form this compound. Remember that Fluorine has -1 charge (F-1) and there are 4 of them. That means that Sn must have a +4 charge; therefore, the compound would be called: Tin(IV) fluoride or Stannic fluoride.
This toothpastes contain sodium fluoride (NaF), tin fluoride (SnF2), sodium monofluorophosphate(NaPO3F), etc. as fluoride source.
The formula is SnF2.
The formula of tin(IV) hydroxide Sn(OH)4.
The formula for Tin IV Phosphate is: Sn3(PO4)4
The formula for the tin four ion is Sn+4
It is an Ionic Compound (also referring to an metal forming with multiple ions). The following in "common name" is SnF2= Stannous Flouride and in IUPAC form SnF2= Tin (II) Flouride