SnF2
The chemical symbol of tin is Sn; the cation can be Sn2+ or Sn4+.
First we have to start by determining what charge does Sn have to form this compound. Remember that Fluorine has -1 charge (F-1) and there are 4 of them. That means that Sn must have a +4 charge; therefore, the compound would be called: Tin(IV) fluoride or Stannic fluoride.
Formula: XF3 where X is the element with which fluorine is bonded
The chemical formula for tin(II) hydroxide is Sn(OH)2.
The chemical formula of barium fluoride is BaF2.
The ionic formula for tin fluoride is SnF2. The tin ion has a 2+ charge, while the fluoride ion has a 1- charge, so one tin ion combines with two fluoride ions to balance out the charges.
The formula for tin(II) fluoride is SnF₂. In this compound, tin has a +2 oxidation state, while each fluoride ion has a -1 charge. Therefore, two fluoride ions are needed to balance the charge of one tin ion, resulting in the formula SnF₂.
Snt2
SnF4
SnF2 is stannous- or tin(II) fluoride
Tin(II) fluoride is a compound composed of one tin atom and two fluoride atoms chemically bonded together. It is not a mixture, as mixtures are combinations of two or more substances that are physically combined but not chemically bonded.
SnF4
The chemical symbol of tin is Sn; the cation can be Sn2+ or Sn4+.
The class of Tin II Fluoride is an inorganic compound. It is a metal fluoride containing tin in the +2 oxidation state.
The formula is SnF2.
because tin is in +2 oxidation state (lower oxidation state of tin)
It is an Ionic Compound (also referring to an metal forming with multiple ions). The following in "common name" is SnF2= Stannous Flouride and in IUPAC form SnF2= Tin (II) Flouride