manpower X3
By Voltage output and capacity in Amp hours.
Yes,provided that the power output of the investor is higher than the motor's rated power.
The mechanical load of a motor determines the necessary output power rating of an electric motor. As mechanical loads are defined in terms of watts (or, in North America, horse power), then motor's output must be rated in watts, too.The so-called 'power' rating of a transformer is determined by the rated voltage and the rated current of its secondary winding. The product of these two quantities is the transformer's rated 'apparent power', expressed in volt amperes.Incidentally, the symbol for "kilowatts" is "kW", not"KW's"!
It's the maximum mechanical power (either in horsepower or kilowatts) that the motor can deliver without overheating or overloading. You need to look at the nameplate (if it has one), or get the manufacturer's specs. It's difficult to know what the output is otherwise.
Presumably you mean 'rated full-load current'? The thing to remember is that motors, whether rated in horsepower (North America) or watts (practically everywhere else), are rated according to their output power. Because motors are not 100% efficient, the input power is always somewhat higherthan the output power. 0.5 horsepower is equivalent to about 373 W output power. If we assume that the motor runs at, say, 90% efficiency at its rated output, this means its input power will be around 414 W. To determine its input current you must then divide its input power by the rated supply voltage.
Here’s the technical specifications of weigh bridgeSpecification of LOAD CELL GRADE Rated Capacities Rated output Total Error* Zero Return after 30 mins Temperature EffectOn Output: On Zero Zero Balance Temperature rangeOperating Compensated Safe Overload Ultimate Overload ExcitationMaximum Input impedance Output Impedance Insulation Impedance Deflection at Rated Capacity WeightEnvironmental Protection Cable E 40klb 3.0 mV/V ±0.25% 0.050±% of Applied Load 0.050±% of Applied Load 0.004±% of Applied Load/*C 0.007±% of Rated output/*C 3.0± of Rated Output -30Deg. C to + 80 Deg. C -10 Deg. C to + 40 Deg. C 150% of rated capacity 300% of Rated Capacity 10 Volts AC or DC 15 Volts AC or DC 780±20 Ohms 705±5 Ohms.
Maximum current is defined by the rated KW of the device, say Motor. The motor may not run at its maximum rated capacity all the time. Nominal current is drawn when motor runs at nominal load.
Since (in North America, at least), the horsepower of a motor describes its rated output power, you need to know its efficiency in order to determine its input power, then its rated voltage, to determine its full-load current.
What effect will be there on the motor (Induction) output power when a 100kW 50hz motor is connected to a 60hz power supply.
The monitor is an output device......
Yes, it is generally safe to start an AC motor with an inverter that has a higher power rating. The inverter's capacity should exceed the motor's power requirements to ensure sufficient starting torque. However, it is important to ensure that the inverter is correctly configured and that the motor is compatible with the inverter's voltage and frequency output.
motor output