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A dog is running at 6.45 m/s. His human calls to him and 3.19 seconds later he is running at 6.56 m/s. What is his acceleration during this time?
0.034 m/s/s
If I pushed on the gas pedal for 4 seconds and changed the velocity by 9 m per s how do I calculate the acceleration.?
Acceleration = change in velocity/time, so we havea = 9/4 m/s/s = 2.25 m/s/s
Find the time interval of acceleration?
You want to take your change in velocity(Final Velocity - Initial Velocity)(Vi - Vf) (8.3 m/s - 5.0 m/s = 3.3m/s). The, you divide it by your average acceleration (0.50 m/s^2) (3.3m/s ÷ 0.50 m/s^2 = 6.6 m/s) So the Final Formula is t =(Vf - Vi) ÷ a
How do you you find the speed with 5 meters and 30 seconds?
Since speed is distance traveled per unit of time, divide the distance by the time. Something that moves 5 meters in 30 seconds has an average speed of 5/30 m/s, which simplifies to 1/6 m/s, which is approximately 0.1667 m/s or 16.67 cm/s. If you prefer, you can multiply 0.1667 m/s by 3600 s/hr and divide it by 1000 m/km, giving you about 0.6 km/hr.
How do you find the velocity of an object that has fallen 10 m?
Assuming the the object was dropped and is relatively close to the earth's surface; then we can say that since: distance=(1/2)(acceleration)(time)2 ; 10m=(1/2)(9.8)(time)2 ; then the time spent falling is apprx. 1.429s, multiplied by the acceleration (9.8 m/s2) gives us a velocity of apprx. 14.00 m/s
What has the author Edward M Stanton written?
Edward M. Stanton has written: 'Branch stores: planning, merchandising, operating, promoting' -- subject(s): Chain stores
What time does macy open and close?
What time does Macy s open today and close d
A runner covers the last straight stretch of a race in 4 s during that time he speeds up 5 m s to 9 m s what is the runbers acceleration in this part of the race?
Vi = 5 m/s A = (V_f- V_i )/t = (9 m⁄s- 5 m⁄s )/(4 sec) = (4 m⁄s )/(4 sec) = Vf = 9 m/s Change in time = 4 sec
What has the author S M James written?
S. M. James has written: 'Time in primary mathematics'
Can marks Spencer vouchers be used in Melbourne Australia?
Are you serious? There are no M&S stores in Australia.
Why do units of acceleration have two time units?
Acceleration = (v - u)/t Replace each variable in the equation with their units Acceleration = (m/s - m/s) / s Same common denominator (m - m/s)/s Apply divison of fractions (m-m)/s*s (m/s^2) Note: I know m - m = 0 but they are just units expressing metres!
When the bus decelerates uniformly at 5 point 3 m per s2 it slows from 8.5 m per s to 0 m per s what is the time interval of acceleration for the bus?
Vf = V0 + at --> 0 = (8.5 m/s) - (5.3 m/s²)t -> t = (8.5 m/s)/(5.3 m/s²) = 1.60377 s
A dog is running at 6.45 m/s. His human calls to him and 3.19 seconds later he is running at 6.56 m/s. What is his acceleration during this time?
0.034 m/s/s
If the speed of an object changes from 121 m/s to 98 m/s during a time interval of 12 s, what is the acceleration of the object?
B -1.92 m/s2
A swimmer speeds up from 1 point 1 m s to 1 point 3 m s during the last 20 s of a workout What is the swimmers acceleration during the last time interval?
Acceleration is the change in velocity with time. In the metric system it is measured in meters per second per second (meters/seconds squared). In your example just subtract the initial speed from the final speed and divide the difference by the time. So: 1.3 m/s - 1.1 m/s = 0.2 m/s. Divide 0.2 m/s by 20 s to get an acceleration of .01 m/s per s.
What forces are difined as?
Acceleration is the change in velocity (m/s) divided by time (s), which is the same as meters divided by time in seconds squared (m/s2).
What has the author S M Karbacey written?
S. M. Karbacey has written: 'Time optimal feedback control of linear multivariable discrete-time systems with input time-delay'
