The isotope of zirconim, 91Zr, has 51 neutrons. 40Zr(91) is a stable isotope with 51 neutrons
Its atomic number is 40, and its mean Atomic Mass is 91.22.
91.(22) - 40 = 51 neutrons
41Nb(92) is an unstable isotope with 51 neutrons
Nb = Niobium
Atomic number is 41, 92 - 41 = 51 neutrons
protons: 51 electrons: 51 neutrons:70
Isotope 89Y and isotope 90Zr has 50 neutrons.
Protones = 51 Electrones = 49 Neutrones = 70 or 72
This is the isotope zirconium-93 (51 n + 2 n =53 n plus 40 p).
You think probable to the isotope iron-56.
Period 10? Check the spelling !
It's Zirconium.
The isotope of zirconim, 91Zr, has 51 neutrons. In order to solve this problem, one must know that an element's atomic weight is the average of its number of protons and neutrons (only neutrons are variable). Since the atomic number is the number of protons, the atomic number subtracted from the atomic weight gives the number of neutrons. An element in period 5 that has this many neutrons is found to be zirconium (the isotope 91Zr).
protons: 51 electrons: 51 neutrons:70
28 neutrons
51 protons, 51 electrons and 70 neutrons (in Antimony-171 isotope)
Number of neutrons depends on the isotope. Number of neutrons = Mass number - Atomic number V-51 isotope has 28 neutrons (51 - 23 = 28)
Isotope 89Y and isotope 90Zr has 50 neutrons.
Antimony (symbol Sb) has three isotopes: 121Sb, 123Sb, and 125Sb. The 121 isotope has 70 neutrons, and the 123 isotope has 72 neutrons. The 125 isotope isn't stable and will decay, but it has 74 neutrons.
Protones = 51 Electrones = 49 Neutrones = 70 or 72
51
This is the isotope zirconium-93 (51 n + 2 n =53 n plus 40 p).