The isotope of zirconim, 91Zr, has 51 neutrons. 40Zr(91) is a stable isotope with 51 neutrons
Its atomic number is 40, and its mean Atomic Mass is 91.22.
91.(22) - 40 = 51 neutrons
41Nb(92) is an unstable isotope with 51 neutrons
Nb = Niobium
Atomic number is 41, 92 - 41 = 51 neutrons
The transition metal with 51 neutrons is the element cobalt, which has an atomic number of 27.
A transition metal with 51 neutrons in period 5 is Molybdenum (Mo), which has an atomic number of 42. To find the specific isotope with 51 neutrons, you would add the atomic number (42) to the number of neutrons (51), resulting in a mass number of 93 (42 + 51). Therefore, the isotope of Molybdenum with 51 neutrons is Molybdenum-93.
The element you are referring to is Zirconium (Zr), which has an atomic number of 40 and is located in period 5 of the periodic table. Since Zirconium has 40 protons, having 51 neutrons gives it an atomic mass of approximately 91 (40 protons + 51 neutrons). This places it specifically as the isotope Zirconium-91.
121Sb has 71 neutrons. This can be calculated by subtracting the atomic number of antimony (Sb), which is 51, from the mass number, which is 121.
Isotope 89Y and isotope 90Zr has 50 neutrons.
The transition metal with 51 neutrons is the element cobalt, which has an atomic number of 27.
A transition metal with 51 neutrons in period 5 is Molybdenum (Mo), which has an atomic number of 42. To find the specific isotope with 51 neutrons, you would add the atomic number (42) to the number of neutrons (51), resulting in a mass number of 93 (42 + 51). Therefore, the isotope of Molybdenum with 51 neutrons is Molybdenum-93.
The isotope of zirconim, 91Zr, has 51 neutrons. In order to solve this problem, one must know that an element's atomic weight is the average of its number of protons and neutrons (only neutrons are variable). Since the atomic number is the number of protons, the atomic number subtracted from the atomic weight gives the number of neutrons. An element in period 5 that has this many neutrons is found to be zirconium (the isotope 91Zr).
The element with 51 neutrons is antimony (Sb), which is a metalloid. Being in period 5, it belongs to the transition elements in the periodic table, showing typical metallic properties and variable oxidation states in its compounds.
The element you are referring to is Zirconium (Zr), which has an atomic number of 40 and is located in period 5 of the periodic table. Since Zirconium has 40 protons, having 51 neutrons gives it an atomic mass of approximately 91 (40 protons + 51 neutrons). This places it specifically as the isotope Zirconium-91.
The element you are referring to is the element Antimony (Sb), which has an atomic number of 51 and belongs to period 5 of the periodic table.
Vanadium 51 has 29 neutrons. This is calculated by subtracting the atomic number (21) from the atomic mass (51) of the element.
51 protons, 51 electrons and 70 neutrons (in Antimony-171 isotope)
121Sb has 71 neutrons. This can be calculated by subtracting the atomic number of antimony (Sb), which is 51, from the mass number, which is 121.
Number of neutrons depends on the isotope. Number of neutrons = Mass number - Atomic number V-51 isotope has 28 neutrons (51 - 23 = 28)
Isotope 89Y and isotope 90Zr has 50 neutrons.
An element with an atomic number of 51 and 51 neutrons is antimony (Sb). Antimony has an atomic mass of approximately 102, which is the sum of its protons (51) and neutrons (51). In the context of the periodic table, it is located in period 5 and group 15.