Between the copper and the sulfate, CuSO4, there is an ionic bond.
Cu 2+
and
SO4 2-
---------------
The hydrated part, water, is a polar covalent molecule with the unequal sharing of electrons between the oxygen atom and the two hydrogen atoms.
In copper (II) sulfate pentahydrate (CuSO4ยท5H2O), there are ionic bonds between copper ions (Cu2+) and sulfate ions (SO4) as well as hydrogen bonds between water molecules (H2O) and the sulfate ions.
The reaction between copper oxide (CuO) and sulfuric acid (H2SO4) produces copper sulfate (CuSO4) and water (H2O). The balanced chemical equation for this reaction is: CuO + H2SO4 -> CuSO4 + H2O
CuSO4 * 5H2O ----> CuSO4 + 5H2O. This is true because CuSO4 * 5 H2O is a salt weakly bounded to water, that is why it is hydrous. When it decomposes, the weak bonds are broken making the products above. CuSO4*5H2O formula is [Cu(OH2)4]SO4*H2O CuSO4 + 5H2O --> [Cu(OH2)4]SO4*H2O
The balanced equation for CuSO4 is: CuSO4 โ Cu + SO2 + O2.
To calculate the grams of copper sulfate needed to produce 29.8g of water, you need to consider the molar mass of water and copper sulfate. Then use stoichiometry to determine the amount of copper sulfate needed.
H2O (water) has hydrogen bonds between its molecules. NH3 (ammonia) has hydrogen bonds between its molecules as well, in addition to covalent bonds within the molecule itself.
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
To calculate the grams of copper sulfate needed to produce 29.8g of water, you need to consider the molar mass of water and copper sulfate. Then use stoichiometry to determine the amount of copper sulfate needed.
penta = 5 copper(II) sulphate pentahydrate = CuSO4*5 H2O CuSO4*5 H2O + heat --> CuSO4 + 5 H2O
The balanced equation for CuSO4 is: CuSO4 โ Cu + SO2 + O2.
H2O CuSo4 Ca2So4
The reaction between copper oxide (CuO) and sulfuric acid (H2SO4) produces copper sulfate (CuSO4) and water (H2O). The balanced chemical equation for this reaction is: CuO + H2SO4 -> CuSO4 + H2O
These are some possible ionic equation for CuSO4 plus H2O: Cu2+ + 6 H2O --> Cu(H2O)6 Cu(H2O)62+ + H2O <--> Cu(OH)(H2O)5+ + H3O+ This makes a solution of copper sulfate weakly acidic.
CuSO4 * 5H2O ----> CuSO4 + 5H2O. This is true because CuSO4 * 5 H2O is a salt weakly bounded to water, that is why it is hydrous. When it decomposes, the weak bonds are broken making the products above. CuSO4*5H2O formula is [Cu(OH2)4]SO4*H2O CuSO4 + 5H2O --> [Cu(OH2)4]SO4*H2O
In its crystallic (solid) form there are 5 molecules H2O regularly build in the crystal lattice, not ionically but rather polar hydrogen bonds strong enough to keep'm in place: CuSO4.(H2O)5
CuCO3(s) + H2SO4(aq) → CuSO4(aq) + CO2(g) + H2O(l)
Copper sulfate dissolves in water, it does not react.