formaldehyde is sp2 hybradized and is trigonal planar.
sp3
Xe belongs to the noble gas family so has 8 valence electrons...Xe => 5s25p6....... Two of these are bonded with fluorine. Thus it is left with 6 electronss i.e. 3 lone pairs.... So hybridization is sp3d ....the shape that should be =>Trigonal bipyramidal.... But it has 3 lone pairs on equatorial plane & 2 bond pairs on axial .....so final shape =>LINEAR...
sp2. Each carbon is sp2 hybridised leaving a p orbital that can form a pi bond. The ethylene (ethene) molecule is planar.
There wont be a stable compound with the formula C2Br2. If there is then it will be sp hybridization of carbon. If the question is for CH2Br2, then carbon will be sp3 hybridized.
sp2 with 120 degree bond angles.
in single bond hybridization will be sp3 and take tetrahedral shape as in CH4 in double bond hybridization will be sp2 and take planar triangle shape as in C2H4in triple bond hybridization will be sp and take linear shape as in C2H2
Sp3 hybridization because of the three Hydrogens coming off of the Nitrogen plus one lone pair of electrons on the Nitrogen to satisfy it's octet rule.
Yes.
sp3
Go to: www.google.com Type in: purchase formaldehyde It will give you a list of places that sell it.
Xe belongs to the noble gas family so has 8 valence electrons...Xe => 5s25p6....... Two of these are bonded with fluorine. Thus it is left with 6 electronss i.e. 3 lone pairs.... So hybridization is sp3d ....the shape that should be =>Trigonal bipyramidal.... But it has 3 lone pairs on equatorial plane & 2 bond pairs on axial .....so final shape =>LINEAR...
Type of hybridization of molecule.
Formaldehyde, HCHO, is an example of an aldehyde (or carbonyl compounds)
No. Polyquaternium-10 uses quaternary ammonium as a functional group. This is different from formaldehyde, which has an aldehyde as the functional group.
sp2. Each carbon is sp2 hybridised leaving a p orbital that can form a pi bond. The ethylene (ethene) molecule is planar.
There wont be a stable compound with the formula C2Br2. If there is then it will be sp hybridization of carbon. If the question is for CH2Br2, then carbon will be sp3 hybridized.
sp^3 d