As we know that the sampling rate is two times of the highest frequency (Nyquist theorm)
Sampling rate=2 Nyquist
fs=8000hz/8khz
>8000hz
4000
It is: (4000-1000)/4000 times 100 = 75% decrease
Solution Let fh is the highest frequency and fl is the lowest frequency. Bandwidth = fh - fl = 4000 - 40 KHz = 3960 KHz = 3.96 MHz
4000
4000 quarts = 1000 gallons math 4000/4=1000
1000 g = 1 kg → 4000 g = 4000 ÷ 1000 kg = 4 kg
LCM(800, 1000) = 4000.
4000
a.100-200m b.400-600m c.1000-2000m d.4000-6000m
4000
4000