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What velocity if a body strike the ground which was dropped from the height of 176.4m?
Mf1997
The formula for a socalled "free fall" velocity (v in m/s) is:
v = SQRT [2.g.h]
in which g = 9,81 m/s2 (mean gravitational accelleration on earth) and h is the falling highth in metres.
Calculating: v = SQRT[2 * 9.81 * 176.4] = SQRT[3461] = 58.8 m/s
So, ONLY if no resistance (eg. from air) is conteracting the force by gravity, then the velocity at ground level will be 58.8 meter per second and by then this is also independent from the falling mass (theoretically).
However, depending on measures, mass and surface area and roughness, the air resistance can play a major role in decreased veleocity: look at hail, rain drops, and fogg: same density, different surface, and fogg will never reach ground (!), but I would like to miss being bombed by large hail stones from 150 m high!
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