It depends on the current load. If you're only pulling low amperage, the voltage drop will be minimal. If you're attempting to pull anywhere near 20 amps, the voltage drop will be considerable. It also depends on the type and quality of the wire.
The voltage drop depends on the current through the cable.For DC current in cable of 16 mm diameter, at 68° F, the voltage drop is(0.00857) x (current, Amperes) volts.
For appliances that need a lot of power, the advantage of a higher voltage is that less current is needed, because power = voltage x current. That means that the cable doesn't need to be so thick. It also means that for a given percentage of voltage drop in the cable, the allowable volt-drop in the cable is higher when the supply voltage is higher. This also allows the use of a thinner cable especially when the cable is 100 ft long or more.
The percentage voltage drop is calculated using the formula: [ \text{Percentage Voltage Drop} = \left( \frac{V_{drop}}{V_{supply}} \right) \times 100 ] where ( V_{drop} ) is the voltage drop across the load or conductor, and ( V_{supply} ) is the supply voltage. Measure the voltage at the load and subtract it from the supply voltage to find ( V_{drop} ). Then, apply the formula to express the voltage drop as a percentage of the supply voltage.
This is a voltage drop question and a voltage needs to be stated.
This is a voltage drop to establish wire size question. For a correct answer to this question two values are needed. One value needed is the voltage and the other is whether it is three phase or a single phase installation.
It depends on the material of the cable (aluminum or copper) and the gauge of the cable. (Thickness). And on the current you intend it to carry.
For a 100 amp main panel located 100 feet away, it is recommended to use a 2/0 copper or 4/0 aluminum service cable to ensure proper voltage drop and capacity for the distance. Consult with a licensed electrician to determine the specific requirements based on local codes and conditions.
Wattage is really what is needed. If you are working with DC voltage, Ohm's Law is at work. But to answer your question directly probably a #4 wire. <<>> To answer this question the circuit's voltage needs to be stated. Then a voltage drop calculation can be made.
This is a voltage drop question. A voltage must be stated to answer this question.
A resistor in parallel with a voltages source will not cause the voltage to drop, theoretically. To get a 20 volt drop you need a resistance in series, and the number of ohms is 20 divided by the current in amps. If the current is unknown or variable, the voltage can't be dropped by using a resistor.
For a 240-volt, 50-amp circuit at 100 feet in length, you would need to use a 6-gauge wire. This wire size ensures that you have minimal voltage drop over the distance, allowing your circuit to operate safely and efficiently. Make sure to consult local electrical codes and regulations before proceeding with the installation.
This is a voltage drop question. To answer this question a voltage has to be stated. The higher the voltage to the circuit becomes the smaller the wire size needed. After a certain voltage point the wire size will remain constant and the voltage drop at the load will become smaller.