The voltage drop depends on the current through the cable.
For DC current in cable of 16 mm diameter, at 68° F, the voltage drop is
(0.00857) x (current, Amperes) volts.
This is a voltage drop question. To answer this question a voltage has to be stated. The higher the voltage to the circuit becomes the smaller the wire size needed. After a certain voltage point the wire size will remain constant and the voltage drop at the load will become smaller.
For a 240-volt, 50-amp circuit at 100 feet in length, you would need to use a 6-gauge wire. This wire size ensures that you have minimal voltage drop over the distance, allowing your circuit to operate safely and efficiently. Make sure to consult local electrical codes and regulations before proceeding with the installation.
It depends on the current flowing in the wire. V=IR. The wires have resistance (easily calculated, approx. .32 ohms for 200 feet of wire (100 feet out and back)). If 20 amps are flowing in the circuit the the voltage drop is about 6.4 volts. That means you're converting electricity to heat in the wires at a rate of about 130 Watts. If less current is flowing then there is a smaller voltage drop in the wire.
Actual voltage would be 240V. 4 AWG copper is capable of carrying 50A. At 200 ft, with a 50A load, voltage drop would be about 6V, which is within the acceptable 3% voltage drop for a branch circuit.
It is not advisable to run a 20 amp circuit 150 feet without understanding the specific electrical load requirements and potential voltage drop over distance. It's important to consult with a licensed electrician to ensure the safe and efficient operation of the circuit over that distance.
If the voltage is supplying any current through the cable, i.e. if there is any 'load' at the end, then the voltage will drop through the cable.
There is voltage drop over any sysetm that does not have infinitely low resistance, but with reasonable cable size there would be very little drop over 200 metres. The number of phases makes little difference.
It depends on the voltage that the motor needs, because a higher voltage requires less current for a given amount of power. Also a higher voltage can tolerate a higher voltage drop. So there are two things that lead to a thinner wire when the voltage is higher.
This is a voltage drop question. To answer this question a voltage must be given.
A 2/0 AWG copper conductor will limit the voltage drop to 3% or less when supplying 65 amps for 150 metres on a 240 volt system.
AC card have over/under voltage adjustment for fault. If voltage drop to that range it will trip the fault. Also the unit have voltage adjustment in the bottom right. Voltage coming out of the cable vs voltage coming out Underwood can be different.
Voltage drop due to the resistance present in the series circuit causes voltage split over a series circuit.
Unanswerable. You need to specify the core size and material. Using two 10 AWG wires with a diameter of 2.6 mm each, the voltage drop over 1500 metres would be less than 1 volt.
Well, isn't that a lovely question! To power a 20kVA load over 320 meters, you'll want to use a cable size that can handle the electrical current without losing too much energy along the way. I recommend consulting with a local electrician or engineer to determine the specific cable size needed based on factors like voltage drop, cable type, and installation conditions. Just remember, with the right guidance, you'll create a beautiful and safe electrical connection for your needs.
A wire size of 250 MCM will limit the voltage drop to 3% over a distance of 200 feet.
This is a voltage drop question. To answer this question a voltage has to be stated. The higher the voltage to the circuit becomes the smaller the wire size needed. After a certain voltage point the wire size will remain constant and the voltage drop at the load will become smaller.
A 1 in 80 fall over 4.5 meters indicates a slope where for every 80 units of horizontal distance, there is a vertical drop of 1 unit. To calculate the vertical drop over 4.5 meters (4500 mm), you can use the ratio: (4500 mm / 80) = 56.25 mm. Therefore, over 4.5 meters, the slope would have a vertical drop of approximately 56.25 mm.