The chemical equation is:
Ba(NO3)2 + Na2SO4 = BaSO4 + 2 NaNO3
The volume (in mL) of 0,25M Na2SO4 solution needed to precipitate all the barium as BaSO4(s) from 12,5mL of 0,15M Ba(NO3)2 solution is 7,5 mL.
A solution of barium chloride is added to a solution of potassium chromate, a yellow precipitate forms.
Nothing - barium chloride is soluble. You can however precipitate either the barium (e.g. with sodium sulphate, giving barium sulpate, or the chloride, e.g. with silver nitrate giving silver chloride precipitate.
Calcium. It reacts with water to form a solution of calcium hydroxide which can then react with carbon dioxide to form calcium carbonate, a white precipitate. You will get similar results with strontium and barium.
Correctly it should be written as 'Ba(NO3)2 ' and it is barium nitrate. Notice the use of brackets and the '2' , to indicate that there are two nitrate anions combined to the one barium cation. NB As you gave it, it does not make sense as a chemical formula.
To identify the presence of sulfate ions in a solution, follow these steps: To acidify the sample, add a few drops of dilute hydrochloric acid (HCl) to the sample. Then, add a few drops of dilute barium chloride (BaCl2) solution to the sample. If sulfate ions are present in the solution, a white precipitate of barium sulfate (BaSO4) will form. The reaction is: Ba²⁺ (aq) + SO4²⁻ (aq) → BaSO4 (s) For example, if we have a solution of magnesium sulfate (MgSO4), the reaction would be: BaCl2 (aq) + MgSO4 (aq) → BaSO4 (s) + MgCl2 (aq) By observing the formation of the white precipitate, we can confirm the presence of sulfate ions in the sample.
White precipitate of barium sulphate
Barium nitrate is soluble in water.
Since barium chloride is reactive with sulfate ions there would be more precipitate present. The solution with more precipitate present would show it had higher amounts of sulfate ions
This is barium nitrate, an inorganic ionic salt.
A solution of barium chloride is added to a solution of potassium chromate, a yellow precipitate forms.
Adding a solution of Sodium Sulphate to aqueous Barium Nitrate will produce a white precipitate of Barium Sulphate with Sodium Nitrate remaining in solution.
My friend, it would appear you have a solution containing barium ions. If you would like add some sulfuric acid to precipitate the barium as barium sulfate.
The precipitate will be barium sulfate. The reaction is as follows:BaCl2(aq) + Na2SO4(aq) ==> 2NaCl(aq) + Ba(SO4)(s)
Yes, it is correct.
The barium ion in barium hydroxide and sulfate ion in sulfuric acid combine to form barium sulfate, which is insoluble in water.
The immediate response is a milky appearance. After 5-10 minutes a precipitate of BaSO4 will settle out of solution. You will obtain a cloudy, white precipitate that will remain so infantily. This is a precipitation reaction (the formation of an insoluble salt from a solution of soluble ones) which occurs because barium sulfate is insoluble, so when mixed, the barium ions react with the sulfate ions to form a white precipitate of barium sulfate The net ionic equation is: Ba2+(aq) + SO42-(aq) ----> BaSO4(s)
whencalcium chloride reacts with barium nitrate calcium nitrate and barium chloride wil be formed. whencalcium chloride reacts with barium nitrate calcium nitrate and barium chloride wil be formed.