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What volume of 0.131 M BaCl2 is required to react completely with 42.0 ml of .453 MNa2SO4. This is the net ionic equation for the reaction. Ba2 plus plus SO42---- BaSO4. Correct answer equals 145 ML?
Wiki User
∙ 11y ago
first of all, you need to recognize that one mole of Na2SO4 is reacting with one mole of BaCL2. so find the moles of the NaSO4, then you automatically have the moles of the BaCL2. if you get the moles of the BaCL2, its easy to calculate the volume of it because you already have the MOLARITY. good luck
Wiki User
∙ 11y ago
To find the volume of BaCl2 needed to react completely, use the stoichiometry of the balanced equation. First, calculate the moles of Na2SO4 using its provided concentration and volume. Then, use the balanced equation to determine that it reacts in a 1:1 ratio with BaCl2. Finally, convert the moles of Na2SO4 to volume of BaCl2 using its molarity. The correct volume should be found as 145 mL.
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