This reaction is correct.
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
Keq=[H2][Cl2]/[hcl]^2
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
For the reaction 2HCl(g) ==> H2(g) + Cl2(g), the Keq = [H2(g)][Cl2(g)]/[HCl(g)]^2
The balanced equation is H2+ Cl2 --> 2HCl That is with a lowercase L, not an i.
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
Keq=[H2][Cl2]/[hcl]^2
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
For the reaction 2HCl(g) ==> H2(g) + Cl2(g), the Keq = [H2(g)][Cl2(g)]/[HCl(g)]^2
The balanced equation is H2+ Cl2 --> 2HCl That is with a lowercase L, not an i.
The reaction produces heat.
H2 + Cl2 2HCl
H2 + Cl2 --> 2HCl
in the reaction of H2 and Cl2 hydrogen is oxidised. Chlorine is reduced.
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
The balanced equation is as follows: Mg + 2HCl --> MgCl2 + H2