This reaction is correct.
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
The equilibrium constant (K eq) for the reaction 2HCl(g) ⇌ H2(g) + Cl2(g) would be [H2][Cl2]/[HCl]^2, where the square brackets indicate the molar concentrations of the respective species at equilibrium.
hydrogen + chlorine = HCl H2 + Cl2 = 2HCl
The chemical equation is not balanced. It should be balanced as follows: H2 + Cl2 → 2HCl
Keq=[H2][Cl2]/[hcl]^2
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
The equilibrium constant (K eq) for the reaction 2HCl(g) ⇌ H2(g) + Cl2(g) would be [H2][Cl2]/[HCl]^2, where the square brackets indicate the molar concentrations of the respective species at equilibrium.
hydrogen + chlorine = HCl H2 + Cl2 = 2HCl
The chemical equation is not balanced. It should be balanced as follows: H2 + Cl2 → 2HCl
Keq=[H2][Cl2]/[hcl]^2
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
The equilibrium constant, K_eq, for the reaction 2HCl(g) ⇌ H2(g) + Cl2(g) is equal to the concentration of H2 and Cl2 divided by the concentration of HCl squared, as products are in the numerator and reactants in the denominator.
The balanced equation is H2+ Cl2 --> 2HCl That is with a lowercase L, not an i.
The reaction produces heat.
H2 + Cl2 2HCl
H2 + Cl2 --> 2HCl