The balanced equation is H2+ Cl2 --> 2HCl
That is with a lowercase L, not an i.
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
Keq=[H2][Cl2]/[hcl]^2
For the reaction 2HCl(g) ==> H2(g) + Cl2(g), the Keq = [H2(g)][Cl2(g)]/[HCl(g)]^2
This reaction is correct.
in the reaction of H2 and Cl2 hydrogen is oxidised. Chlorine is reduced.
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
ZnCl2 + H2 formed
Keq=[H2][Cl2]/[hcl]^2
For the reaction 2HCl(g) ==> H2(g) + Cl2(g), the Keq = [H2(g)][Cl2(g)]/[HCl(g)]^2
This reaction is correct.
cl2 means chlorine, 02 means oxygen (2 oxygen atoms) h2 means hydrogen (2 hydrogen atoms)
H2 + Cl2 2HCl
H2 + Cl2 --> 2HCl