in the reaction of H2 and Cl2 hydrogen is oxidised. Chlorine is reduced.
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
In the reaction MnO2 + 4HCl -> MnCl2 + Cl2 + 2H2O, manganese in MnO2 is getting oxidized from +4 to +2 (in MnCl2). Chloride ions in HCl are being reduced to chlorine gas (Cl2).
Aluminium.
The equilibrium constant, K_eq, for the reaction 2HCl(g) ⇌ H2(g) + Cl2(g) is equal to the concentration of H2 and Cl2 divided by the concentration of HCl squared, as products are in the numerator and reactants in the denominator.
The balanced equation is H2+ Cl2 --> 2HCl That is with a lowercase L, not an i.
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
The chemical equation is not balanced. It should be balanced as follows: H2 + Cl2 → 2HCl
In the reaction MnO2 + 4HCl -> MnCl2 + Cl2 + 2H2O, manganese in MnO2 is getting oxidized from +4 to +2 (in MnCl2). Chloride ions in HCl are being reduced to chlorine gas (Cl2).
Aluminium.
The equilibrium constant (K eq) for the reaction 2HCl(g) ⇌ H2(g) + Cl2(g) would be [H2][Cl2]/[HCl]^2, where the square brackets indicate the molar concentrations of the respective species at equilibrium.
The equilibrium constant, K_eq, for the reaction 2HCl(g) ⇌ H2(g) + Cl2(g) is equal to the concentration of H2 and Cl2 divided by the concentration of HCl squared, as products are in the numerator and reactants in the denominator.
Keq=[H2][Cl2]/[hcl]^2
HCl + NaOH = H2O + NaCl is already balanced.
In the reaction N2 + 3H2 → 2NH3, nitrogen (N2) is reduced because it gains hydrogen atoms, and hydrogen (H2) is oxidized because it loses electrons.